iOS String format

Question

I have the following issue in swift

I have a String

let GET_LISTING = "Listing/GetDetails?deviceid=%@&listingid=%d";

the I use this line to get it formatted

let url = SERVER_URL + String.localizedStringWithFormat(GET_LISTING, deviceId, listingId);

when the number < 1000 it works fine

for example

Listing/GetDetails?deviceid=AB11F1D0-153E-48C3-950F-CC773BBCC683&listingid=500

if number > 1000 it is wrong

Listing/GetDetails?deviceid=AB11F1D0-153E-48C3-950F-CC773BBCC683&listingid=1,050

how can I solve this problem ?

Is there a stringWithFormat function instead of localizedStringWithFormat? — rmaddy
– rmaddy, Commented May 6, 2016 at 23:45
Try let url = SERVER_URL + String.localizedStringWithFormat(GET_LISTING, deviceId, String(listingId)); — Fernando Reynoso
– Fernando Reynoso, Commented May 6, 2016 at 23:48
There is a String(format:, arguments:) constructor in swift. Also, you should consider using String interpolation: "Listing/GetDetails?deviceid=\(deviceId)&listingid=\(listingId)" — Palle
– Palle, Commented May 6, 2016 at 23:52

vacawama · Accepted Answer · 2016-05-06 23:56:53Z

4

You could convert the listingId to a String:

let GET_LISTING = "Listing/GetDetails?deviceid=%@&listingid=%@"
let url = SERVER_URL + String.localizedStringWithFormat(GET_LISTING, deviceId, String(listingId))

edited May 6, 2016 at 23:56

answered May 6, 2016 at 23:49

vacawama

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2 Comments

Amira Elsayed Ismail Over a year ago

you mean let GET_LISTING = "Listing/GetDetails?deviceid=%@&listingid=%@"

vacawama Over a year ago

Sure. I thought %s would work, but %@ certainly should. Changed it.

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