How to solve getting json data with python

Question

im very new in python programming, so i created the following python script in order to iterate in a folder which contain 3000 or more json files, and i dont know how to iterate in those 3000 json files to do not put manually in the script, and i need to put a specific path where are the json files located as well and i dont know how to declare it.

import json
all_results = {}
json_file_list = ['1.json', '2.json']
for file in json_file_list:
     with open(file) as json_file:
    json_data = json.load(json_file)
    for key, value in json_data.iteritems():
       if 'result' in value:
            all_results[key] = value['result']
return all_results

after run my python script i have the following error :

File "getResult.py", line 20
  return all_results
SyntaxError: 'return' outside function

and this is how looks like my jsons files

{ "igt@gem_reloc_overflow@single-overflow": { "type": "TestResult", "command": "/home/gfx/intel-graphics/intel-gpu-tools/tests/gem_reloc_overflow --run-subtest single-overflow", "dmesg": "", "environment": "PIGLIT_PLATFORM=\"mixed_glx_egl\" PIGLIT_SOURCE_DIR=\"/home/gfx/intel-graphics/intel-gpu-tools/piglit\"", "err": "(gem_reloc_overflow:19562) CRITICAL: Test assertion failure function reloc_tests, file gem_reloc_overflow.c:260:\n(gem_reloc_overflow:19562) CRITICAL: Failed assertion: gem_execbuf(fd, &execbuf) == -14\n(gem_reloc_overflow:19562) CRITICAL: error: -22 != -14\nSubtest single-overflow failed.\n**** DEBUG ****\n(gem_reloc_overflow:19562) DEBUG: relocation_count=4294967295\n(gem_reloc_overflow:19562) CRITICAL: Test assertion failure function reloc_tests, file gem_reloc_overflow.c:260:\n(gem_reloc_overflow:19562) CRITICAL: Failed assertion: __gem_execbuf(fd, &execbuf) == -14\n(gem_reloc_overflow:19562) CRITICAL: error: -22 != -14\n**** END ****\n", "exception": null, "out": "IGT-Version: 1.14-g1e9a3ac (x86_64) (Linux: 4.6.0-rc4-drm-intel-nightly-ww17-commit-1e81bac+ x86_64)\nStack trace:\n #0 [__igt_fail_assert+0x101]\n #1 [reloc_tests+0x6d6]\n #2 [+0x6d6]\nSubtest single-overflow: FAIL (8.469s)\n", "pid": 19562, "result": "fail", "returncode": 99, "subtests": { "__type": "Subtests" }, "time": { "type": "TimeAttribute", "end": 1462072402.5360818, "start": 1462072393.7328644 }, "traceback": null } }

any help is welcome, thanks

John Zwinck · Accepted Answer · 2016-05-08 04:58:33Z

0

Perhaps you want print all_results instead of return all_results. Or you could print them one by one as they are found.

answered May 8, 2016 at 4:58

John Zwinck

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Community · Accepted Answer · 2017-05-23 12:31:41Z

0

To iterate over the files in a directory without having to enter the filenames manually, you can use os.walk() or os.listdir(). See this question for more details.

The syntax error seems pretty self-explanatory. You have a return statement that is not inside of a function definition; this is invalid Python. If you want to output the results, use print.

edited May 23, 2017 at 12:31

CommunityBot

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answered May 8, 2016 at 5:03

augurar

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1 Comment

shaveax Over a year ago

thanks, but with this command : onlyfiles = [f for f in listdir(mypath) if isfile(join(mypath, f))] , i have only the json files names, and i need the full path with the names because python shows me that it cant find the files

Tanu · Accepted Answer · 2016-05-08 06:54:12Z

0

Store the path of JSON file directory to a variable

mypath = "/home/json_file_directory"

Use os.listdir() to list all the json files.

Once you have json filename,use

 os.path.join(mypath,filename) #to get the exact path of file.

answered May 8, 2016 at 6:54

Tanu

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