how can I display all the data from database using an array

Question

I'm trying to connect $countries to an array that will display all the data from my database, it only displays the last data I entered.Is there anyway I can display all of them?

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
     die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT product_id, product_name , quantity FROM inventory";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
     // output data of each row
     while($row = $result->fetch_assoc()) {
        $tom = array(" ". $row["quantity"] . $row["product_name"]);
         $countries = $tom;
     }
} else {
     echo "0 results";
}

$conn->close();

$countries[] = $tom;

Alex
– Alex

2016-05-12 13:11:56 +00:00
Commented May 12, 2016 at 13:11 — Alex
– Alex, Commented May 12, 2016 at 13:11

Jayesh Chitroda · Accepted Answer · 2016-05-12 13:10:33Z

1

because you have assinged data to $countries with wrong manner:

$countries = array();
if ($result->num_rows > 0) {
     // output data of each row
     while($row = $result->fetch_assoc()) {
        $tom = array(" ". $row["quantity"] . $row["product_name"]);
        $countries[] = $tom; // use []
     }
} else {
     echo "0 results";
}

answered May 12, 2016 at 13:10

Jayesh Chitroda

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1 Comment

Jayesh Chitroda Over a year ago

@user3153327 welcome :) mark it correct if you found it useful

Excalibrus · Accepted Answer · 2016-05-12 13:13:30Z

0

 $countries[] = $tom;

With [] at the end of inicialization of variable you add a row to that array. If you do it without [], it's just inicialization every time in while loop.

answered May 12, 2016 at 13:13

Excalibrus

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Comments

Mohammedshafeek C S · Accepted Answer · 2016-05-12 13:20:19Z

0

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
     die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT product_id, product_name , quantity FROM inventory";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
     // output data of each row
     while($row = $result->fetch_assoc())         
         $countries[] = " ". $row["quantity"] . $row["product_name"];     
} else {
     echo "0 results";
}

$conn->close();

answered May 12, 2016 at 13:20

Mohammedshafeek C S

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Your Common Sense · Accepted Answer · 2016-05-12 14:55:03Z

0

// create connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($servername, $username, $password, $dbname);

// get the data
$sql = "SELECT product_id, product_name, quantity FROM inventory";
$countries = $conn->query($sql)->fetch_all();

Although it's only available with mysqlnd installations, you need one, because without mysqlnd mysqli is unusable anyway.

edited May 12, 2016 at 14:55

answered May 12, 2016 at 13:28

Your Common Sense

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