Extracting a string format using lua

Question

I have a string

(A file location) = "C:\User\Projects\54a2135.tif"

There are several tiff files in the location and I will need to pick them and move them to a different folder.

My difficulty is in getting only the .tif file . I tried string.match, string.gsub, string.find but unable to achieve that. Is there any advice on how I extract just the .tif file (In this case 54a2135.tif) from that string?

Yu Hao · Accepted Answer · 2016-05-13 08:35:46Z

2

To start with, \ is the escape character, so it should be escaped in double/single quoted strings. (The other option is to use the long string [[...]])

Then you can use pattern matching:

local path = "C:\\User\\Projects\\54a2135.tif"
print(path:match("[^\\]*$"))

The pattern [^\\]*$ matches any non-backslash characters at the end of the string.

If you like to specify it's a .tif file, change the pattern to [^\\]*%.tif$

answered May 13, 2016 at 8:35

Yu Hao

123k50 gold badges252 silver badges305 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Eric David Over a year ago

Thank you so much Yu Hao. It worked like a charm. I appreciate your help. Cant thank you enough...

Collectives™ on Stack Overflow

Extracting a string format using lua

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related