How to add an integer value into NSMutableArray?

Question

NSMutableArray * val;
val = [[NSMutableArray alloc] initWithCapacity:15];

/*int outlineWidth = barOutlineWidth;
int outlineHalfWidth = (outlineWidth > 1) ? outlineWidth * 0.5f : 0;
 */
for ( Bar * obj in values )
{  
  // calcualte the bar size
  float value  = [obj value];
  float scale  = ( value / maxValue );

  // shift the bar to the top or bottom of the render line
  int pointY   = lineHeight + ( (lineWidth * 0.5f) * ( ( value >= 0.0f ) ? -1 : 1 ) );
  int barHeight = height * scale;
  NSLog(@"%d", barHeight);   
  CGRect barRect = CGRectMake(pointX, pointY, width, -barHeight);
  [val addObject:[NSNumber numberWithInt:barHeight]];
                     NSLog(@"%d", val);

I want to add the barheight (int) into array val. Is this possible? while running the code,

session started at 2010-09-16 13:21:50 +0530.]
2010-09-16 13:21:53.791 BarGraphSample[3168:20b] 78
2010-09-16 13:21:53.797 BarGraphSample[3168:20b] 69398112
2010-09-16 13:21:53.807 BarGraphSample[3168:20b] 235
2010-09-16 13:21:53.812 BarGraphSample[3168:20b] 69398112
2010-09-16 13:21:53.813 BarGraphSample[3168:20b] 156
2010-09-16 13:21:53.814 BarGraphSample[3168:20b] 69398112

this is the output.

Here the actual barheights are 78,235,156, while printing the array val.

Im getting like values like "69398112"

What should I do?

Greg Sexton · Accepted Answer · 2010-09-16 08:14:47Z

50

You can only add pointers to objects to an NSMutableArray. If you use the NSNumber class though to wrap your integer, you should then be able to add that to the array.

int x = 10;
NSNumber* xWrapped = [NSNumber numberWithInt:x];
NSMutableArray* array = [[NSMutableArray alloc] initWithCapacity:15];
[array addObject:xWrapped];
int xOut = [[array lastObject] intValue]; //xOut == x;

Hope this helps.

edited Sep 16, 2010 at 8:14

answered Sep 16, 2010 at 8:04

Greg Sexton

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3 Comments

jer Over a year ago

xOut will be an NSNumber* not an int, unless you also pass intValue to the object returned by lastObject.

Shaggy Frog Over a year ago

By "pointers" I think you mean "objects" -- e.g. adding a char* would still require wrapping it up in an object.

Greg Sexton Over a year ago

I see your point but I don't completely agree. Firstly, I did say 'pointers to objects'. A char* wouldn't really fall into that as I would say that is a pointer to a primitive type. Secondly, you are adding a pointer to an object to the array. In the example above I add xWrapped, which is an NSNumber pointer.

jer · Accepted Answer · 2013-06-03 17:46:41Z

20

Add a number instead.

NSNumber* foo = [NSNumber numberWithInteger:42];

or using boxed literals:

NSNumber* foo = @(42);

then add foo.

edited Jun 3, 2013 at 17:46

answered Sep 16, 2010 at 8:02

jer

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Comments

Venk · Accepted Answer · 2013-06-03 07:28:26Z

1

The issue is with your NSLog string namely

NSLog(@"%d", val);

%d is in fact the format specifier for an integer (int). You are passing it a NSMutableArray object.

Change the NSLog to

NSLog(@"%@", val);

The %@ expects an object, and this will typically print out [myObject description], in this case a description of your val array.

edited Jun 3, 2013 at 7:28

Venk

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answered Sep 17, 2010 at 15:09

Richard Turnbull

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Comments

Shadros · Accepted Answer · 2016-02-25 07:58:53Z

1

Convert Int to NSNumber then add to your array

answered Feb 25, 2016 at 7:58

Shadros

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Comments

Pedro Trujillo · Accepted Answer · 2017-11-26 03:33:42Z

1

This is a simple way: @(yourInt)

int value = 5;
NSMutableArray * anArray  = [[NSMutableArray alloc] init];
[anArray addObject: @(value)];

more information about at-compiler-directives

answered Nov 26, 2017 at 3:33

Pedro Trujillo

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