PHP how to echo variable name

Question

I'm kinda confused in my case,

$counts="$s{$process[$count]}";

if i echo $counts with

echo "$counts";

it still showing the value, how can i echo $counts to show the variable name

$steamroller

(in this case the process is 'team', and count is 'roller')) instead of the value of the variable $system?

EDIT okay i found it by myself it should be

$counts='$s'.$process."[".$count."]";

thank you..

Just use single quotes instead of double quotes in echo statement plz check here: 3v4l.org/VZHG8 — Ali
– Ali, Commented May 17, 2016 at 4:53
Possible duplicate of stackoverflow.com/questions/255312/… — Noman Ghani
– Noman Ghani, Commented May 17, 2016 at 4:56
@Ali that's not what i mean, the $steamroller itself is a variable that has a value, so every time i echo $count it always showing the value of $steamroller instead of "$steamroller", the wrong thing i think is how i save the variable in $counts — unknown.person
– unknown.person, Commented May 17, 2016 at 4:59
@FrayneKonok im sorry sir, i rate up your answer yesterday, maybe my internet connection is down, after i check again this time, my rate up and green check is missing, looks like it wasnt make it, sorry :) — unknown.person
– unknown.person, Commented May 18, 2016 at 4:10

Murad Hasan · Accepted Answer · 2016-05-17 04:56:10Z

2

Just make this:

$s = 's';
$count = 1;
$process[$count] = 'teamroller';

echo $counts = "$$s{$process[$count]}"; // $steamroller

answered May 17, 2016 at 4:56

Murad Hasan

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Hossein · Accepted Answer · 2016-05-17 04:58:22Z

2

if you echo variable name in "" , php parse that variable an echo its value, if you want echo variable name with '' like this:

echo '$counts';

answered May 17, 2016 at 4:58

Hossein

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