How do I check if user input is found in array?

Question

I'm trying to check if user input is equal to the data I have in my arrays, then printing the int array that corresponds with the string array, but nothing appears when I run the program.

What am I doing wrong?

This is everything I have in my main method:

  String firstname;
  String middleinitial;

  System.out.println("What is your first name?");
  firstname = myScan.nextLine();

  System.out.println("What is your middle initial?");
  middleinitial = myScan.nextLine();

 String[] firstNameLetter = {"A", "Albert", "Alice", "Ann", "Anna", "Annie",        "Arthur", 
            "B", "Bernard", "Bette", "Bettie", "Betty", "C", "Carl",
            "Catherine", "Charles", "Clara", "D", "Donald", "Dorothy, E",
            "Edward", "Elizabeth", "F", "Florence", "Frank", "G", "George",
            "Grace", "H", "Harold", "Harriet", "Harry", "Hazel", "Helen",      "Henry",
            "I", "J", "James", "Jane", "Jayne", "Jean", "John", 
            "Joan", "Joseph", "K", "L", "M", "Margaret", "Martin",
            "Marvin", "Mary", "Melvin", "Mildred", "N", "O", "P",
            "Patricia", "Paul", "Q", "R", "Richard", "Ruby", "Robert",
            "Ruth", "S", "T", "Thelma", "Thomas", "U", "V",
            "W", "Walter", "Wanda", "William", "Wilma", "X", "Y",
            "Z"};

    int[] firstNameNumber     = {000, 020, 020, 040, 040, 040, 040,
             060, 80, 80, 80, 80, 100, 120,
             120, 140, 140, 160, 180, 180, 200,
             220, 220, 240, 260, 260, 280, 300,
             300, 320, 340, 340, 360, 360, 380, 380,
             400, 420, 440, 440, 440, 460, 460,
             480, 480, 500, 520, 540, 560, 560,
             580, 580, 600, 600, 620, 640, 660,
             680, 680, 700, 720, 740, 740, 760,
             760, 780, 800, 820, 820, 840, 860,
             880, 900, 900, 920, 920, 940, 960,
             980};

String[] middleNameLetter = {" ", "A", "B", "C", "D", "E", "F",
             "G", "H", "I", "J", "K", "L", "M",
             "N", "O", "P", "Q", "R", "S", "T",
             "U", "V", "W", "X", "Y", "Z"};

int[] middleNameNumber    = {0, 1, 2, 3, 4, 5, 6,
                             7, 8, 9, 10, 11, 12, 13,
                             14, 14, 15, 15, 16, 17, 18,
                             18, 18, 19, 19, 19, 19};

for (int count = 0; count < firstNameLetter.length; count++)
{
    if (firstname.equals(firstNameLetter[count]))
    {
        System.out.println(firstNameNumber[count]);
    }
}

for (int count = 0; count < middleNameLetter.length; count++)
{
    if (middleinitial.equals(middleNameLetter[count]))
    {
        System.out.println(middleNameNumber[count]);
    }
}

for my opinion,if you can use hashMap,it will be more better than array.for example Map map = new HashMap();map.put(000,"abc"),map.put(002,"def").then if you want to check user input is contain ,then you can do like that:for (ArrayList<String> value: map.values()) { // using ArrayList#contains System.out.println(value.contains("myString")); }.then you can also print the key easily. — sawyinwaimon
– sawyinwaimon, Commented May 20, 2016 at 3:26

Monny Star · Accepted Answer · 2016-05-20 03:37:22Z

When I ran this code myself all seemed to be working. I see nothing wrong with your logic. You must have a typo in there somewhere.

public static void main(String[] args) {

    Scanner myScan = new Scanner(System.in);
    String firstname;
    String middleinitial;

    System.out.println("What is your first name?");
    firstname = myScan.nextLine();

    System.out.println("What is your middle initial?");
    middleinitial = myScan.nextLine();

    String[] firstNameLetter = {"A", "Albert", "Alice", "Ann", "Anna", 
        "Annie","Arthur", "B", "Bernard", "Bette", "Bettie", "Betty", 
        "C", "Carl", "Catherine", "Charles", "Clara", "D", "Donald", 
        "Dorothy, E", "Edward", "Elizabeth", "F", "Florence", "Frank", 
        "G", "George", "Grace", "H", "Harold", "Harriet", "Harry", "Hazel",
        "Helen", "Henry", "I", "J", "James", "Jane", "Jayne", "Jean", 
        "John", "Joan", "Joseph", "K", "L", "M", "Margaret", "Martin",
        "Marvin", "Mary", "Melvin", "Mildred", "N", "O", "P",
        "Patricia", "Paul", "Q", "R", "Richard", "Ruby", "Robert",
        "Ruth", "S", "T", "Thelma", "Thomas", "U", "V",
        "W", "Walter", "Wanda", "William", "Wilma", "X", "Y",
        "Z"};

    int[] firstNameNumber = {000, 020, 020, 040, 040, 040, 040,
                             060, 80, 80, 80, 80, 100, 120,120,
                             140, 140, 160, 180, 180, 200, 220, 
                             220, 240, 260, 260, 280, 300, 300,
                             320, 340, 340, 360, 360, 380, 380,
                             400, 420, 440, 440, 440, 460, 460,
                             480, 480, 500, 520, 540, 560, 560,
                             580, 580, 600, 600, 620, 640, 660,
                             680, 680, 700, 720, 740, 740, 760,
                             760, 780, 800, 820, 820, 840, 860,
                             880, 900, 900, 920, 920, 940, 960, 980};  

    String[] middleNameLetter = {" ", "A", "B", "C", "D", "E", "F",
                                 "G", "H", "I", "J", "K", "L", "M",
                                 "N", "O", "P", "Q", "R", "S", "T",
                                 "U", "V", "W", "X", "Y", "Z"};

    int[] middleNameNumber = {0, 1, 2, 3, 4, 5, 6,
                              7, 8, 9, 10, 11, 12, 13,
                              14, 14, 15, 15, 16, 17, 18,
                              18, 18, 19, 19, 19, 19};

    for (int count = 0; count < firstNameLetter.length; count++) {
        if (firstname.equals(firstNameLetter[count])) {
            System.out.println(firstNameNumber[count]);
        }
    }

    for (int count = 0; count < middleNameLetter.length; count++) {
        if (middleinitial.equals(middleNameLetter[count])) {
            System.out.println(middleNameNumber[count]);
        } 
    }
}

there's a "typo" in the logic if he wants those first 8 integers as their integer values and not their octal values :)

Saif Charaniya · Accepted Answer · 2016-05-20 03:22:13Z

0

You might want to try equalsIgnoreCase() instead of equals() and may also want to add a break statement in the for loops to stop iterating if the strings match.

answered May 20, 2016 at 3:22

Saif Charaniya

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Comments

Ryan Waskiewicz · Accepted Answer · 2016-05-20 03:29:05Z

0

As a sanity check, are you able to recompile this successfully? In trying to run your solution I found the Scanner instance was not being declared. Adding the following: Scanner myScan = new Scanner(System.in);

allowed me to run with following output:

$java ScannerTest
What is your first name?
Henry
What is your middle initial?
A
380
1

answered May 20, 2016 at 3:29

Ryan Waskiewicz

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2 Comments

user6359011 Over a year ago

yeah whoops I had scanner declared in my original code i forgot to paste it in here i'm sorry about that

Ryan Waskiewicz Over a year ago

Does that solve the issue? Or are you still having issues getting it to recognize your input?

ΦXocę 웃 Пepeúpa ツ · Accepted Answer · 2016-05-20 03:30:30Z

0

You can turn the array into a list and use the method. list.contains() Arrays.asList(firstNameLetter).contains(firstname);

etc etc for all the given inputs

edited May 20, 2016 at 3:30

answered May 20, 2016 at 3:29

ΦXocę 웃 Пepeúpa ツ

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1 Comment

Daniel Widdis Over a year ago

That won't give him the int in the second array.

Daniel Widdis · Accepted Answer · 2016-05-20 03:38:26Z

0

Your program is working correctly (other than the missing Scanner myScan = new Scanner(System.in); that you likely have and didn't repeat).

What may be confusing you is that you've defined several of your integers as octal values. When you begin an integer with a 0 value it is declared as an octal.

For example, the second value, corresponding to Albert, is 020. This is an octal value for 16.

As others have mentioned, you likely want to use equalsIgnoreCase() on your strings and break; from inside the loops. Also having two equal length arrays is dangerous; much better to store the values in pairs in a HashMap or other structure.

answered May 20, 2016 at 3:38

Daniel Widdis

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Comments

bakely · Accepted Answer · 2016-05-20 04:39:45Z

0

if(str.toLowerCase().equals())

answered May 20, 2016 at 4:39

bakely

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