Folder and File creating with bash scripting

Question

I have to create 50 folders and each fifth folder should have 2*2 files in it, e.g

folder1
.
.
folder5 - has 2 files in it
folder 6
.
.
folder 10 - has 4 files in it 
.
.
folder 15 - has 8 files in it

here is my code :

#!/bin/bash


n=1 
declare -i countFolder

for (( countFolder = 1; countFolder <= 50; countFolder++ )) 
do 
    mkdir Folder$countFolder
done

for (( countFolder = 5; countFolder <= 50; countFolder = countFolder+5 ))
do

    let "n = n * 2"

    for (( f = 0; f < n; f++ )) do
    cd Folder$countFolder && touch File$f.txt
    done
done

Why is this question marked with python tag?

SivNiz
– SivNiz

2016-05-26 00:14:13 +00:00
Commented May 26, 2016 at 0:14 — SivNiz
– SivNiz, Commented May 26, 2016 at 0:14

that other guy · Accepted Answer · 2016-05-26 00:15:20Z

2

The problem with this is that you cd into a directory but you never cd back.

The simplest way of fixing this is by adding parentheses around the cd. These parentheses start a subshell, so the cd stays within it:

for (( f = 0; f < n; f++ )) do
  ( cd Folder$countFolder && touch File$f.txt ) 
done

This is equivalent to but shorter than a manual cd ..:

for (( f = 0; f < n; f++ )) do
  cd Folder$countFolder && { touch File$f.txt; cd ..; }
done

answered May 26, 2016 at 0:15

that other guy

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1 Comment

Barmar Over a year ago

Or just touch Folder$countFolder/File$f.txt

Jon McClung · Accepted Answer · 2016-05-26 00:20:24Z

1

You need to go into the directory, make your files, then leave. The most efficient way to do this is the following:

#!/bin/bash


n=1 
declare -i countFolder

for (( countFolder = 1; countFolder <= 50; countFolder++ )) 
do 
    mkdir Folder$countFolder
    ls
done

for (( countFolder = 5; countFolder <= 50; countFolder = countFolder+5 ))
do

    let "n = n * 2"
    cd Folder$countFolder
    for (( f = 0; f < n; f++ )) do
        touch File$f.txt
    done
    cd ..
done

answered May 26, 2016 at 0:20

Jon McClung

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