I have a quick question.
I am trying to split a string S : 'greenland.gdb\topology_check\t_buildings' at '\' using:
S.split('\')
I expect output list :
['greenland.gdb', 'topology_check', 't_buildings'].
Instead it returns error : SyntaxError: EOL while scanning string literal. What is with character '\' in python. With any other character it works fine.
You need to escape the backslash:
S.split('\\')
You may also need to string_escape:
In [10]: s = 'greenland.gdb\topology_check\t_buildings'
In [11]: s.split("\\")
Out[11]: ['greenland.gdb\topology_check\t_buildings']
In [12]: s.encode("string_escape").split("\\")
Out[12]: ['greenland.gdb', 'topology_check', 't_buildings']
\t would be interpreted as a tab character unless you were using a raw string:
In [18]: s = 'greenland.gdb\topology_check\t_buildings'
In [19]: print(s)
greenland.gdb opology_check _buildings
In [20]: s = r'greenland.gdb\topology_check\t_buildings'
In [21]: print(s)
greenland.gdb\topology_check\t_buildings
You need to use a raw string first, 'r' or 'R' as follows:
In [01]: s = r'greenland.gdb\topology_check\t_buildings'
Then split while remembering to escape the backslash
In [02]: s.split('\\')
Out [02]: ['greenland.gdb', 'topology_check', 't_buildings']
Quoting from re — Regular expression operations (Python documentation)
\Either escapes special characters (permitting you to match characters like '*', '?', and so forth), or signals a special sequence; special sequences are discussed below.If you’re not using a raw string to express the pattern, remember that Python also uses the backslash as an escape sequence in string literals; if the escape sequence isn’t recognized by Python’s parser, the backslash and subsequent character are included in the resulting string. However, if Python would recognize the resulting sequence, the backslash should be repeated twice. This is complicated and hard to understand, so it’s highly recommended that you use raw strings for all but the simplest expressions.
Backslash \ is a special character , I dont like magic too but ,
in this case (and for both python 2.7 and python 3 ):
>>> s = 'greenland.gdb\topology_check\t_buildings'
>>> s.split()
will give the desired output :
['greenland.gdb', 'opology_check', '_buildings']
s = 'greenland.gdb**\topology_check\t**_buildings' python is consider this \t has the escape sequence . \t - Indicates the whitespace in python.
for the above case we won't specify any separater .space considered as default separater. input- print (s.split()) output- ['greenland.gdb', 'opology_check', '_buildings']
If I am wrong correct me .
