Find string using regex javascript

Question

I Want to Find string ,whose last character may or may not present

"abc,efg,ASD"
"abc,ASD,efg"

so, i have to find ASD with or without " , "

Are you looking for an exact match on an element of a comma-separated list? For example, "abc,efg,ASD" or "abc,ASD,efg" should match (looking for ASD) but "abc,efg,ASDF" or "abc,ASDF,efg" should not? — Fred Willmore
– Fred Willmore, Commented May 28, 2016 at 17:21
I read it as if you needed ASD from the first string, and ASD, from the second. The criteria are not clear: get all non-word chars after ASD but whitespace (/\bASD[^\w\s]*/)? Or an optional comma (/\bASD,?/)? — Wiktor Stribiżew
– Wiktor Stribiżew, Commented May 28, 2016 at 20:50

Ro Yo Mi · Accepted Answer · 2016-05-28 17:50:37Z

Description

[,"](ASD)[,"]

Regular expression visualization

This regular expression will do the following:

match the asd between commas or comma and quote,
place the value into capture group 1

Example

Live Demo

https://regex101.com/r/mV9vA9/1

Explanation

NODE                     EXPLANATION
----------------------------------------------------------------------
  [,"]                     any character of: ',', '"'
----------------------------------------------------------------------
  (                        group and capture to \1:
----------------------------------------------------------------------
    ASD                      'ASD'
----------------------------------------------------------------------
  )                        end of \1
----------------------------------------------------------------------
  [,"]                     any character of: ',', '"'
----------------------------------------------------------------------

j4hangir · Accepted Answer · 2016-05-28 17:15:00Z

0

Does this answer your question?

var regex = /,ASD,?/g;
var result = regex.exec("abc,ASD\nabc,ASD,dsa");
console.log(result);

answered May 28, 2016 at 17:15

j4hangir

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