Converting dataframe to factor automatically

Question

I am trying to remove duplicates

laa <-subset(la,select =c(PermID))

class(laa)

laa1<-laa[!duplicated(laa$userPermID), ]

class(laa1)

when i ran first two lines the class command is showing it as data.frame but after running the duplicate command it is converting into factor automatically. Is there any specific reason. Because iam not able to see it in dataframe

Most probably, it was already a factor when it was still in the data.frame. Use str instead of class for some more info — talat
– talat, Commented May 30, 2016 at 6:52

Community · Accepted Answer · 2020-06-20 09:12:55Z

1

As we are only selecting the 'PermID' in the first step, the default option while subsetting the rows with [ having a single column data.frame would be drop=TRUE resulting in a vector instead of a data.frame. Assuming that 'PermID' is a factor column, the class of the vector will be factor. To avoid that, use drop=FALSE.

laa1 <- laa[!duplicated(laa$userPermID), , drop=FALSE]

The class(laa1) would be data.frame.

If we look at the documentation ?"[", the default usage is

x[i, j, ... , drop = TRUE]

drop: For matrices and arrays. If TRUE the result is coerced to the lowest possible dimension (see the examples). This only works for extracting elements, not for the replacement. See drop for further details.

edited Jun 20, 2020 at 9:12

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answered May 30, 2016 at 6:52

akrun

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