How to put a shell variable into a curl command in a shell script?

Question

I am trying to execute curl commands from my shell script on OSx el Capitan. How can i pass a variable to the curl script. I tried this: var ="some variable" curl -O '$var' But its not working. Thanks in advance

Do you also have space between var and ="some variable" in your script? And what does "its not working" mean? — jDo
– jDo, Commented May 30, 2016 at 17:53
Yes its a long string of data and the variable changes everytime to give me a 200 OK , but it doesn't . — kshitij Nigam
– kshitij Nigam, Commented May 30, 2016 at 17:56

Phillip Mills · Accepted Answer · 2016-05-30 17:54:49Z

1

Single quotes may be preventing interpolation of the variable. Try this as a sample:

export var="http://www.google.com/"
curl "$var"

answered May 30, 2016 at 17:54

Phillip Mills

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3 Comments

kshitij Nigam Over a year ago

My bad am using a bunch of data not just the url so its curl -O --data 'random data=$var& some other data'

Phillip Mills Over a year ago

It's the same problem, regardless. Your variable won't be interpolated inside single quotes; you need double ones to get anything except what you literally typed.

kshitij Nigam Over a year ago

Thanks a ton will try this

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