Bash get specific file with name in all directories and run script

Question

This is my scenario, I have a root folder called A, which contains folders B,C,D with n possibilities. Each one of those folders have a bash script. How can I get those bash scripts and run them using bash script.

A/B/run.sh
A/C/run.sh
A/D/run.sh

Oops, you forgot to post your code! StackOverflow is about helping people fix their code. It's not a free coding service. Any code is better than no code at all. Meta-code, even, will demonstrate how you're thinking a program should work, even if you don't know how to write it. — ghoti
– ghoti, Commented May 31, 2016 at 16:17
Thanks for the note I will do that next time, yeah I didn't even know where to begin with since I didn't have any code yet was struggling to get started. — yetanotherposter
– yetanotherposter, Commented May 31, 2016 at 16:39

SLePort · Accepted Answer · 2016-05-31 16:13:16Z

5

With find :

find . -name *.sh -type f -exec bash -c '[[ -x {} ]] || chmod u+x {}; {}' \;

For each *.sh found :

check if file has execute permissions
if not set execute permission for user
execute script

answered May 31, 2016 at 16:13

SLePort

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2 Comments

sjsam Over a year ago

This should be the best recursive solution. :-)

ghoti Over a year ago

I have found bash's globstar feature to be quite a bit faster at finding things recursively than find. YMMV. +1 from me anyway, since this is superior to the embedded ls solution.

Rob · Accepted Answer · 2016-05-31 16:16:18Z

3

easy :)

eval "$(ls A/*/run.sh)"

ls will return a list of file with path to your scripts. (you could use find too)

the " " around the $() will make sure the result keeps new lines

eval will execute the returned lines as a script.

Mind you if there are spaces in the names of your script and stuff this can be a brittle solution. But if it looks like what you have shown, that should work fine.

this is output for an example:

 ~/ eval "$(ls */run.sh)"
 I am running and my name is: one/run.sh
 I am running and my name is: two/run.sh

the run.sh scripts are:

 echo "I am running and my name is: $0"

edited May 31, 2016 at 16:16

answered May 31, 2016 at 16:11

Rob

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3 Comments

sjsam Over a year ago

@yetanotherposter : The other solution is more general and you can easily accommodate non-standard directory names in that.

sjsam Over a year ago

@Rob : This will fail for file say "my_new_line_directory". But yes, this is the most obvious way to do it :-)

ghoti Over a year ago

I would have thought that a for loop would be the most obvious way yo do it. This solution appears to be an implementation of the very first warning on the bash pitfalls list.

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