I'm writing a simple tic tac toe game, and I'm trying to check for different win states. The different tiles are set up in an array, so to check for a win for the three top spaces I have
if (tableArr[0].hasClass('userTaken') && tableArr[1].hasClass('userTaken') && tableArr[2].hasClass('userTaken')){
select(); //ends game
}
I'm looking for a way to shorten this, I tried tableArr[0,1,2].hasClass('userTaken') but that didn't work. Any suggestions?
You could potentially use every for this, but you'd also need to slice the array too. As an example:
tableArr.slice(0, 3).every(x => x.hasClass('userTaken'))
So, take the first three elements of the array using slice, then every checks that the test passes for each of them.
Of course, if this is tic, tac, toe, you'll need to check diagonals too, which is trickier using .slice. You could use map for this too, e.g.
[0,1,2].map(idx => tableArr[idx]).every(x => x.hasClass('userTaken'))
Also you could check if some element doesn't have the class with some :
tableArr.slice(0, 3).some(x => !x.hasClass('userTaken'))