How to decode string to object EXTJS 6

Question

I'm I'm using ExtJS to create a formPanel dynamyc from database (string result from server to object extjs)

Ext.Ajax.request({
     async : false,
     method : 'POST',
     url : '/Devt/GetFormItemCustomization',
     params : {
        TableName : 'tabeltest',
        col : 1
    },
    success : function (response) {
        var results = Ext.decode(response.responseText);
        console.log(results );
        var form = Ext.create('Ext.form.Panel', {
            width : 300,
            bodyPadding : 10,
            renderTo : 'formCustDiv',
            name : "test",
            items : [results]
        });
    }
})

this response from server:

{
   fieldLabel:'Employee Id',
   xtype:'textfield',
   allowBlank:false,
},
{
   fieldLabel:'Nick Name',
   xtype:'textfield',
   allowBlank: false,
}

but this only create one object from last data. Object

{
   fieldLabel: "Nick Name", 
   xtype: "textfield", 
   allowBlank: false
 }

i want response from server decode become two object:

Object {fieldLabel: "Employee Id", xtype: "textfield", allowBlank: false}

Object {fieldLabel: "Nick Name", xtype: "textfield", allowBlank: false}

Any suggests?

Alexander · Accepted Answer · 2016-06-04 09:54:28Z

1

Well, your server should always return valid JSON. Two objects, comma-separated, isn't valid JSON. (You can check with one of the many online JSON validators if you don't believe me.) Could your server possibly return an array of objects? Like this:

[
    {fieldLabel: "Employee Id", xtype: "textfield", allowBlank: false},
    {fieldLabel: "Nick Name", xtype: "textfield", allowBlank: false}
]

In that case, you could easily go ahead and create a form from these by removing the array around the results variable:

var form = Ext.create('Ext.form.Panel', {
        width : 300,
        bodyPadding : 10,
        renderTo : 'formCustDiv',
        name : "test",
        items : results
    });

answered Jun 4, 2016 at 9:54

Alexander

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