Capture the URL in get request in Python

Question

I am writing python code to automate testing to download files. I have downloaded the file by clicking the download icon. What I am trying now is to assert that correct file was downloaded in the background. For this purpose, I need to extract the get request and parameters within. This parameters and URL will contain values to identify if/whether correct document was downloaded.

Can you please help me. Many thanks.

Below is the code I am running.

import os
from selenium import webdriver
from selenium.webdriver.common.keys import Keys

mime_types = "application/pdf,application/vnd.adobe.xfdf,application/vnd.fdf,application/vnd.adobe.xdp+xml"

fp = webdriver.FirefoxProfile()
fp.set_preference("browser.download.folderList", 2)
fp.set_preference("browser.download.manager.showWhenStarting", False)
fp.set_preference("browser.download.dir", os.getcwd())
fp.set_preference("browser.helperApps.neverAsk.saveToDisk", mime_types)
fp.set_preference("plugin.disable_full_page_plugin_for_types", mime_types)
fp.set_preference("pdfjs.disabled", True)


driver = webdriver.Firefox(firefox_profile=fp)
driver.get('site-name')

# login
driver.find_element_by_class_name('textboxUserName').send_keys(name)
driver.find_element_by_id('dummy1').click()
driver.find_element_by_id('content__login_Password').send_keys(pwd)
driver.find_element_by_id('content__login_Password').send_keys(Keys.RETURN)

# search
driver.find_element_by_id('top-search-input').send_keys('9001')
driver.find_element_by_id('top-search-input').send_keys(Keys.RETURN)

# download
driver.find_element_by_xpath("//ul[@class='search-result-list']/li[1]/div/ul/li[7]").click()

As stated earlier, I want to make sure that the file has been downloaded. So I want to get certain values from GET when the button to download is clicked.

thanks

if you want the url, then why not instead of clicking on the download button, you simply fetch the associated link. If this isn't helpful please provide a little bit more information. — Swakeert Jain
– Swakeert Jain, Commented Jun 8, 2016 at 11:18

Swakeert Jain · Accepted Answer · 2016-06-08 19:51:59Z

0

I see two ways you can do that.

Like I mentioned in the comment, you could simply check the 'href' attribute of the download link, instead of clicking it.
Once the program has clicked the link, use:

driver.implicitly_wait(5) #just to be on the safe side

print driver.current_url

Hope this helps.

UPDATE: Based on your comment, if the AJAX ends up opening another window, then this will do the trick:

for handle in driver.window_handles:
    driver.switch_to_window(handle)
    print driver.current_url

edited Jun 8, 2016 at 19:51

answered Jun 8, 2016 at 11:29

Swakeert Jain

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2 Comments

Mustafa Salam Over a year ago

Unfortunately there is no href attribute. It is implemented by Ajax i believe. Also, the code bypasses the native browser save dialogue for downloading file and instead saves it in a predefined location.

Swakeert Jain Over a year ago

Try this then. After around an hour of research this is the best I could find. capture AJAX

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