Regexp for matching executable version number

I'm trying to write a regular expression for matching executable version number.
It can be provided in two ways:

• MAJOR.MINOR.TINY
• MAJOR.MINOR.TINY.BUILD_NUMBER

I do not need to parse these values, just check for match. So, I can: ^\d+[\.\d+]*$. Ok, but this regexp will match strings with 5 and more version parts, i.e 1.2.3.4.5. Also, it will match string like 1..2.3. It would be great to do something like ^[as many digits as you want and only one .]{3,4}$.

P.S. Of course, I can check for something like this ^(\d*)\.(\d*)\.(\d*)$ at first and the for ^(\d*)\.(\d*)\.(\d*)\.(\d*)$ if not matched. But maybe there is a better (smarter) way to do this.

I use re python module for checking the match:

import re

version_regexp = re.compile(r'^\d+[\.\d+]*$')
versions = ['dsvfsdf',
            '1.a.3',
            '1.2.4',
            '1.4..5.6',
            '0.3.1',
            'a.b.c.d',
            '1,2,3']
for i, sample in enumerate(versions):
    print('Sample[%d]: %s' % (i, True if version_regexp.match(sample) else False))

Thank you in advance!