Calling base class in callback for ES6 in NodeJS

Question

For example I have the following class:

class X extends Y
{
   constructor() {  super(); } 

   method() {
      asyncMethod( function( err ) {   
          super.method( err );
      } );
    }
}

However, super is not the base class Y. How can I pass super to that callback?

Is there any solution than using arrow functions?

sfrehse · Accepted Answer · 2016-06-09 07:45:41Z

2

One possible solution is to use arrow functions, e.g.,

asyncMethod( err => super.method( err ) );

answered Jun 9, 2016 at 7:45

sfrehse

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1 Comment

zerkms Over a year ago

Note that depending on the implementation of asyncMethod this code can behave differently (since it returns).

German Latorre · Accepted Answer · 2016-06-09 08:29:19Z

2

I would definitely go with arrow functions but, if you need an alternative, here it goes.

According to JavaScript closures behaviour, you can store a reference to super.method in a variable and use it within the callback.

Here's the code:

class X extends Y
{
   constructor() {  super(); } 

   method() {
      let superMethod = super.method;

      asyncMethod(function (err) {   
          superMethod(err);
      });
   }
}

answered Jun 9, 2016 at 8:29

German Latorre

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