Extracting values from array of arrays

Question

I am trying to extract the three values in each sub array, but it doesnt seem to work. Is there something unusual about the object that is returned, or is my array extraction code incorrect?

#https://github.com/Nedomas/indicators
require 'active_support'
require 'active_support/core_ext'
require 'indicators'

my_data = Indicators::Data.new([1,2,3,4,3,2,4,6,1,2])
temp=my_data.calc(:type => :bb, :params => 2)
puts temp.inspect
temp.output.each do |x| puts "#{x[0]},#{x[1]},#{x[2]}" end

output

king@death-star ~/Desktop/_REPOS/misc/stock_analysis/forex/oanda/ruby $ ruby temp.rb 
#<Indicators::Main:0x00000002c1f9b0 @abbr="BB", @params=[2, 2], @output=[nil, [1.5, 2.914213562373095, 0.08578643762690485], [2.5, 3.914213562373095, 1.0857864376269049], [3.5, 4.914213562373095, 2.085786437626905], [3.5, 4.914213562373095, 2.085786437626905], [2.5, 3.914213562373095, 1.0857864376269049], [3.0, 5.82842712474619, 0.1715728752538097], [5.0, 7.82842712474619, 2.1715728752538097], [3.5, 10.571067811865476, -3.5710678118654755], [1.5, 2.914213562373095, 0.08578643762690485]]>
temp.rb:9:in `block in <main>': undefined method `[]' for nil:NilClass (NoMethodError)
    from temp.rb:9:in `each'
    from temp.rb:9:in `<main>'

Roman Kiselenko · Accepted Answer · 2016-06-10 14:47:45Z

1

According to your output the first value of output variable is nil, you can use compact:

Returns a copy of self with all nil elements removed.

temp.output.compact.each do |x| 
   puts "#{x[0]},#{x[1]},#{x[2]}"
end

answered Jun 10, 2016 at 14:47

Roman Kiselenko

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Ursus · Accepted Answer · 2016-06-10 14:46:50Z

1

First element of your array of array is nil and nil has no method []. You can use compact method to remove nil elements.

http://docs.ruby-lang.org/en/2.0.0/Array.html#method-i-compact

answered Jun 10, 2016 at 14:46

Ursus

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