26

Why does this happen in Angular2 and Typescript?

export class Environment {
    constructor(
      id: string,
      name: string
    ) { }
}


 environments = new Environment('a','b');



app/environments/environment-form.component.ts(16,19): error TS2346: Supplied parameters do not match any signature of call target.

How on do I initialize an array?

1
  • 2
    You can use public data: Array<any> =[]; Commented Oct 6, 2017 at 19:15

6 Answers 6

40

You can use this construct:

export class AppComponent {

    title:string;
    myHero:string;
    heroes: any[];

    constructor() {
       this.title = 'Tour of Heros';
       this.heroes=['Windstorm','Bombasto','Magneta','Tornado']
       this.myHero = this.heroes[0];
    }
}
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Comments

24

you can create and initialize array of any object like this.

hero:Hero[]=[];

2 Comments

how can I set hero to a size of 5?
Is it best practice to initialize the array during declaration like this? Or should you do it in the constructor or in ngOnInit()?
10

Class definitions should be like :

export class Environment {
    cId:string;
    cName:string;

    constructor( id: string, name: string ) { 
        this.cId = id;
        this.cName = name;
    }

    getMyFields(){
        return this.cId + " " + this.cName;
    }
}

 var environments = new Environment('a','b');
 console.log(environments.getMyFields()); // will print a b

Source: https://www.typescriptlang.org/docs/handbook/classes.html

Comments

4

I don't fully understand what you really mean by initializing an array?

Here's an example:

class Environment {

    // you can declare private, public and protected variables in constructor signature 
    constructor(
        private id: string,
        private name: string
    ) { 
        alert( this.id );
    }
}


let environments = new Environment('a','b');

// creating and initializing array of Environment objects
let envArr: Array<Environment> = [ 
        new Environment('c','v'), 
        new Environment('c','v'), 
        new Environment('g','g'), 
        new Environment('3','e') 
  ];

Try it here : https://www.typescriptlang.org/play/index.html

Comments

0

In order to make more concise you can declare constructor parameters as public which automatically create properties with same names and these properties are available via this:

export class Environment {

  constructor(public id:number, public name:string) {}

  getProperties() {
    return `${this.id} : ${this.name}`;
  }
}

let serverEnv = new Environment(80, 'port');
console.log(serverEnv);

 ---result---
// Environment { id: 80, name: 'port' }

Comments

0

hi @JackSlayer94 please find the below example to understand how to make an array of size 5.

class Hero {
    name: string;
    constructor(text: string) {
        this.name = text;
    }

    display() {
        return "Hello, " + this.name;
    }

}

let heros:Hero[] = new Array(5);
for (let i = 0; i < 5; i++){
    heros[i] = new Hero("Name: " + i);
}

for (let i = 0; i < 5; i++){
    console.log(heros[i].display());
}

Comments

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