I knew this 'How can I convert a Java Iterable to a Scala Iterable?'
But I am working on java 1.4.2 code with a scala API.
How can I get a scala.Iterable from a java.util.List?
Thank you for your suggestion.
-
Is that running on a 1.5 or 1.6 JVM, with 1.4 source code, or is it full 1.4? Because Scala 2.8, afaik, does not support Java 1.4.Daniel C. Sobral– Daniel C. Sobral2010-09-23 14:21:16 +00:00Commented Sep 23, 2010 at 14:21
-
It is running with scala 2.7.4 on java 1.4 with a JVM 1.4enguerran– enguerran2010-09-23 14:24:10 +00:00Commented Sep 23, 2010 at 14:24
Add a comment
|
1 Answer
Everything you need is in scala.lang.JavaConversions
import java.util.{List => JList, ArrayList}
import scala.collection.JavaConversions._
val jul1: JList[String] = new ArrayList[String]; jul1.add("Boo!")
val sb1 = jul1.toBuffer
val ss1 = jul1.toSeq // Same result as toBuffer
This produces a mutable collection in sml1 (a Buffer). If you want an immutable collection (List, e.g.) convert that mutable collection:
val sl1 = jul1.toList
Edit: Hmm... Java 1.4.2? That's pre-generics? (I lose track of such ancient history...) This probably won't work, then... You'll probably need to work with existential types.
4 Comments
enguerran
You know in enterprise we have some pre-19700101 code ^^ No elegant method therefore, just loop on java Collection and manual adding in a scala Collection...
Randall Schulz
You said you wanted a
scala.Iterable. I assumed you were writing Scala code that needed to consume a Java collection.enguerran
in fact, I have a scala method to call in my java code (from a scala API a colleague has written) which take for parameters a scala.Iterable. But at this step of my source code, I have a java.util.List in version 1.4.2 (that does not implement java.util.Iterable since it does not exist in 1.4.2). And I would like to call the scala method fed by a scala.Iterable with my "not 1.5 Iterable" java.util.List...
Randall Schulz
Actually, I don't think Scala is compatible with Java 1.4.