Checking for a pattern using regex in jQuery

Question

I'm attempting to use reg ex in jQuery to test whether or not a variable contains a specific pattern, if it does I'm attempting to trim the string. Here's is some pseudo code that details what I need.

     var $test = 12345_4
     if ($test contains '_[0-100]'){
       remove '_' && [0-100]
       // $test would equal 12345
     }
     else {
      //do something
    }

Is it possible to achieve something like this using jQuery? Thanks

jQuery is helpful for things related to the DOM. Do not seek jQuery solutions for other things as it's irrelevant. — plalx
– plalx, Commented Jun 13, 2016 at 13:29
@plalx jQuery has useful things outside of DOM as well. AJAX, iterators etc — alex
– alex, Commented Jun 13, 2016 at 13:51
@alex Why would you use jQuery to iterate over an non-dom nodes array? Use native array functions. As for AJAX it was true for a while, but now that fetch/Request/Promise are getting supported it will become obsolete. — plalx
– plalx, Commented Jun 13, 2016 at 14:00
@plalx In 2009 it was a great idea. You're right it is less useful as browsers are filling in those gaps. — alex
– alex, Commented Jun 13, 2016 at 14:02

anubhava · Accepted Answer · 2016-06-13 13:23:24Z

1

You can use .replace:

var $test = '12345_4'
$test = $test.replace(/_(\d{1,2}|100)\b/g, '')

console.log($test)
// 12345

_(\d{1,2}|100) will match underscore followed by any number between 0 and 100
If match fails your input remains unchanged

answered Jun 13, 2016 at 13:23

anubhava

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Marcos Pérez Gude · Accepted Answer · 2016-06-13 13:23:35Z

0

Yeah, as simple as this:

/[0-9]+(\_[0-9])/

Test it:

https://regex101.com/r/eT9nS3/1

answered Jun 13, 2016 at 13:23

Marcos Pérez Gude

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fdomn-m · Accepted Answer · 2016-06-13 14:06:37Z

0

You can do it 2 ways, using javascript match or replace: here are the examples:

var str = "Visit Microsoft!";
var res = str.replace("Microsoft", "W3Schools");

Result: Visit W3Schools!

var str = "The rain in SPAIN stays mainly in the plain"; 
var res = str.match(/ain/g);

Result: ain,ain,ain

Sources: http://www.w3schools.com/jsref/jsref_replace.asp http://www.w3schools.com/jsref/jsref_match.asp

here are some regular expression cheat sheets, you can use as @marcho have mentioned: http://www.javascriptkit.com/javatutors/redev2.shtml

edited Jun 13, 2016 at 14:06

fdomn-m

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answered Jun 13, 2016 at 13:34

Manam

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