Test if value is in array with underscoreJS using _.some method [duplicate]

Question

let array = [1234, 1233, 1232];

console.log(_.some(array, 1234));

It returns false. Do you know why?

console.log(_.some(array, function(v){ return v === 1234})); — Pranav C Balan
– Pranav C Balan, Commented Jun 14, 2016 at 10:19
Ok fine thanks! Do you maybe know a simpler method to test if a value is in array with underscore? — Xavier C.
– Xavier C., Commented Jun 14, 2016 at 10:22
You could also use _.contains e.g _.contains(array, 1234) — Gruff Bunny
– Gruff Bunny, Commented Jun 14, 2016 at 10:49
Yes, I know why, because I read the documentation for _.some. — user663031
– user663031, Commented Jun 24, 2016 at 5:12

Pranav C Balan · Accepted Answer · 2016-06-24 05:16:13Z

2

As per the documentation of _.some() method, second argument should be a predicate function

console.log(_.some(array, function(v){ return v === 1234}));

In this particular case you can simply use native javascript Array#indexOf method.

console.log(array.indexOf(1234) > -1);

Also there is native JavaScript Array#some method.

console.log(array.some(function(v){ return v === 1234}));

console.log(array.some(v => v == 1234))

answered Jun 14, 2016 at 10:23

Pranav C Balan

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1 Comment

There is also ES5 some and ECMAScript 2015 arrow functions to give: array.some(v=>v==1234). ;-)

Krishnakant · Accepted Answer · 2016-06-24 04:08:24Z

0

With UNDERSCORE.JS you can simply use,

console.log(_.indexOf(array, 1234) >= 0)

answered Jun 14, 2016 at 10:34

Krishnakant

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