PHP implode not getting passed

Question

I'm getting an error that says

Warning: implode():Invalid arguments passed

I do not understand why it is so...

Here is my code.

if(isset($_POST['consultationbutton'])){        
    $image = addslashes(file_get_contents($_FILES['selectedfile']['tmp_name'])); //SQL Injection defence!
    $checkedcondition = implode(",",$_POST['skincondition']);
    $checkedproduct = implode(",",$_POST['skincareinuse']);
    $consultquery="INSERT INTO counsel(nric,dateconsulted,editableface,skincarecurrentlyinuse,skincondition) VALUES('132','$_POST[storedate]','{$image}','$checkedproduct','$checkedcondition')";
    mysqli_query($dbconn,$consultquery);
}

$_POST['skincondition'] and $_POST['skincareinuse'] are the name of my checkboxes.

I gues that $_POST['skincondition'] or $_POST['skincareinuse'] are not arrays. Did you check their contents? — Jakub Matczak
– Jakub Matczak, Commented Jun 15, 2016 at 10:35
Implode works on array have you checked these are array. Try print_r($_POST['skincondition']); just to check — Passionate Coder
– Passionate Coder, Commented Jun 15, 2016 at 10:36
@marcus, I guess you need to use explode here if you need to convert them to string or make the checkbox field name as skincareinuse[] — Nehal
– Nehal, Commented Jun 15, 2016 at 11:00
Yes i didnt set it as arrays in my html, my bad, but thanks guys :) And the implode works fine now, thanks for the input. — mctjl_1997
– mctjl_1997, Commented Jun 15, 2016 at 11:07

Parmjit Singh · Accepted Answer · 2016-06-15 10:56:42Z

2

HTML Part

<form action="" method="post">
<input type="checkbox" name="skincondition[]" value="skincondition_1" />skincondition_1

<input type="checkbox" name="skincondition[]" value="skincondition_2" />skincondition_2

<input type="checkbox" name="skincondition[]" value="skincondition_3" />skincondition_3

<input type="checkbox" name="skincondition[]" value="skincondition_4" />skincondition_4

<input type="checkbox" name="skincondition[]" value="skincondition_5" />skincondition_5

<input type="submit" name="consultationbutton">
</form>

PHP code

if(isset($_POST['consultationbutton'])){        
$checkedcondition = implode(",",$_POST['skincondition']);
echo $checkedcondition;
}

working fine for me, please do share your HTML code so that i can tell you better.

answered Jun 15, 2016 at 10:56

Parmjit Singh

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1 Comment

mctjl_1997 Over a year ago

It worked great now! I placed the name as name="skincondition" forgot to make it into an array, thanks for the help :)

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