how to matching "not" with more chars in java regex pattern?

Question

in java regex,use [^x] to matching "not" with one char.

i want to know,how to matching more chars not?

i using [^789],it's not right.

    String text="aa(123)bb(456)cc(789)dd(78)";
    text=text.replaceAll("\\([^789].*?\\)","");

    System.out.println(text);

i want get result is:

aabbcc(789)dd

how to fix my regex pattern?

thanks a lot :)

Community · Accepted Answer · 2020-06-20 09:12:55Z

7

You can use a negative lookahead:

"\\((?!789\\)).*?\\)"

Explanation:

\\(     Match a literal open parenthesis "("
(?!     Start negative lookahead
789\\)  Match literal "789)"
)       End lookahead
.*?     Match any characters (non-greedy)
\\)     Match a literal close parenthesis ")"

If the pattern inside the negative lookahead matches then negative lookahead fails to match.

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Sep 24, 2010 at 11:16

Mark Byers

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