Python 2.7 Boolean Operators Logic

Question

I am currently in the course of learning Python 2.7 and have come across the Equality and Boolean operators

My question is:

Why False and 1 is False but True and 1 is 1

Likewise, False or 1 is 1 but True or 1 is True

Can someone kindly explain why this is happening

Many thanks

jasonharper · Accepted Answer · 2016-06-17 19:49:19Z

3

and returns the first 'falsy' (False, zero, empty string or list, etc.) value it sees, or the final value if none were falsy. Further values are not even evaluated, since they can't change the result.

or likewise returns the first 'truthy' (True, non-zero, non-empty string or list, etc.) value it sees (or the final one if there were none), and doesn't evaluate the rest.

This behavior is sometimes more convenient than strictly returning only True or False.

answered Jun 17, 2016 at 19:49

jasonharper

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4 Comments

pb_ng Over a year ago

Thank you Jason. I was missing out on the fact that any number other than 0 can also be considered as True.

pb_ng Over a year ago

Btw, going by the above logic, why do you think False or 0 returns 0. In this case both of them are actually Falsies, isn't it?

user4815162342 Over a year ago

@pb_ng Note that the answer does state for the case of or: "or likewise returns the first 'truthy' [...] value it sees (or the final one if there were none)". There are no true values in False or 0, so the last one, 0, is the result.

pb_ng Over a year ago

Thanks a lot for your explanation. It helped!

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