Swift: string url encoding not working as expected

Question

So I have a url like this:

let remoetURL = "http://xxx-test.img-cn-hangzhou.aliyuncs.com/materials/talk_-XXXXX-XXXXXXX/STEM RULE.pdf"

As you can see, at then end of the url, there is a white space, so I need to get rid of it to have a valid encoded url.

After doing some research, I realized I might use

let escapedString = remoteURL.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLPathAllowedCharacterSet())

But this does not returned the expected working url, because it encodes the ":" after "http" too

http%3A//xiaobandeng-staging.img-cn-hangzhou.aliyuncs.com/talk_materials/talk_-K4yjX4-238Ku74WVIJk/STEM%20RULE.pdf

I have also tried URLHostAllowedCharacterSet, but no luck. So I wonder if it is because I don't have www here, so it does not recognise which part is the host correctly. If so, what might be the elegant solution? I know I could replace white spaces with %20 by calling stringByReplacingOccurrencesOfString, but that seems just a bit fragile.

Thank you in advance.

Michael J. Calkins · Accepted Answer · 2017-08-25 17:32:13Z

9

Try this used by SwiftyJSON

let urlString = remoteURL.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())

Swift 3:

let urlString = remoteURL.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)

edited Aug 25, 2017 at 17:32

Michael J. Calkins

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answered Jun 18, 2016 at 9:02

Dhaval Parmar

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2 Comments

Chenglu Over a year ago

This is the right answer. Previously, I was having some misunderstanding towards those NSCharacterSet methods. For URLQueryAllowedCharacterSet , I thought it only deals with the query part of a url, but it turned out to be dealing with the whole url conforming to a valid query format, which will parse spaces, but not slashes.

hnh Over a year ago

This is not really correct, for example this will escape the # anker (e.g. blub/index#hello). I suspect you have to first parse that invalid URL format coming in according to the rules you set, and then construct a proper URL from it.

Nirav D · Accepted Answer · 2016-06-18 11:25:04Z

0

Have you try this

let urlPath = NSString(format: remoetURL).stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)!

For iOS 9

let encodedHost = NSString(format: remoetURL).stringByAddingPercentEncodingWithAllowedCharacters(.URLQueryAllowedCharacterSet())

Hope this will help you

edited Jun 18, 2016 at 11:25

answered Jun 18, 2016 at 7:10

Nirav D

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6 Comments

Chenglu Over a year ago

Thank you! This seems to be the right answer. I actually saw this method before, but don't know why some said it is a deprecated method. But no warning for me, so I guess I should always try before I make a conclusion.

Midhun MP Over a year ago

stringByAddingPercentEscapesUsingEncoding was deprecated in iOS 9.

Chenglu Over a year ago

@MidhunMP, hmm, but there is no warning for me. Then what should I use in this case? Any suggestion?

Midhun MP Over a year ago

@Chenglu: What is your minimum targeted iOS version and the base sdk version ?

Chenglu Over a year ago

@MidhunMP, the targeted is 8.0, and the base is 9.3

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