PHPUnit setUp method

Question

I have a problem. Simple code

use PHPUnit\Framework\TestCase;

class StringTest extends TestCase
{
    protected $stack = '';

    public function testModify()
    {
        $this->stack .= 'modify';
        $this->assertEquals('modify', $this->stack);
    }

    public function testEmpty()
    {
        $this->assertEquals('', $this->stack);
    }

}

Why validation pass? Why in second test $this->stack doesn't has modifyvalue?

Sure, you can write test that depends each other by the result of the first — Matteo
– Matteo, Commented Jun 19, 2016 at 17:59

Sebastian Bergmann · Accepted Answer · 2016-06-19 15:48:11Z

2

Each test (each test method) is run in isolation (on a separate test object).

answered Jun 19, 2016 at 15:48

Sebastian Bergmann

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2 Comments

Mati Over a year ago

I read about it. Is turning off process isolation great idea? I watched a few tutorials and programmers was setting it to false.

Sebastian Bergmann Over a year ago

This is not process isolation, that would give you even more isolation.

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