Assign the result of a loop to a variable in Python [duplicate]

Question

Consider a list I want to parse using a for :

friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
for i in friends:
   print i

will return :

"Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"

However, if I want to put it to a (str) variable, like :

friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
for i in friends:
    var=i

first I have to declare another var variable, which is silly but whatever. then,

print var

will return the last element of the list, which is "Paris", because the variable is overwritten for each iteration right.

So my question is : how can I assign the output of my loop "i", for each iteration, to a variable in Python ?

Sorry for the sillyness of this question but this is a concept I can't seem to figure out clearly.

The answer is probably quite trivial, but I fail to understand what exactly you're asking for. Could you elaborate? What result do you expect? Note that the first example will not result in the output you claim... — skyking
– skyking, Commented Jun 20, 2016 at 8:25
What do you mean "to a variable"? You already have a list, which is assigned to a variable. What variables would you like the items to be assigned to, and why? — jonrsharpe
– jonrsharpe, Commented Jun 20, 2016 at 8:31
To be completely correct, printing and returning are two distinct concepts. Your loop doesn't return anything. — tripleee
– tripleee, Commented Jun 20, 2016 at 8:36
You already have each element in the list stored as a variable: the original list itself. — TigerhawkT3
– TigerhawkT3, Commented Jun 20, 2016 at 8:37

SparkAndShine · Accepted Answer · 2016-06-20 08:32:04Z

2

If I understand well, you'd like to dynamically create variables. Here it is.

from collections import OrderedDict

friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
d = OrderedDict()
for idx, value in enumerate(friends):
    key = 'var' + str(idx)
    d[key] = value 

print(d)
# Output
OrderedDict([('var0', 'Joe'), ('var1', 'Zoe'), ('var2', 'Brad'), ('var3', 'Angelina'), ('var4', 'Zuki'), ('var5', 'Thandi'), ('var6', 'Paris')])

answered Jun 20, 2016 at 8:32

SparkAndShine

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3 Comments

PdevG Over a year ago

wouldn't list(enumerate(friends)) be easier/clearer here?

SparkAndShine Over a year ago

@Skirrebattie, I don't think so. for idx, v in enumerate(l) is widely used.

TigerhawkT3 Over a year ago

Look at your OrderedDict. Now look at friends. Note how you have used several lines of codes to reinvent the list type. The OP's question is fundamentally flawed and any answers cannot possibly be reasonable.

eliasecasta · Accepted Answer · 2019-02-23 08:34:28Z

2

I also have this question, this is how I managed to solve it somewhat:

    friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]

    new_friends = ' '.join([x for x in friends])

    print(new_friends)

Will return:

    Joe Zoe Brad Angelina Zuki Thandi Paris

answered Feb 23, 2019 at 8:34

eliasecasta

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Comments

hb X · Accepted Answer · 2016-06-20 10:10:46Z

1

var = ''
friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
for i in friends:
    var=i

if list and loop are in function then declare var as global

global var

in starting of function

answered Jun 20, 2016 at 10:10

hb X

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1 Comment

Ricardo Over a year ago

This is wrong, as the original question doesn't want var to have the last assignment, but all values.

Irgendniemand · Accepted Answer · 2022-04-19 11:16:27Z

1

I think the easiest & cleanest way for you would be a "List Comprehension", see here.

Here is the respective code:

friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]      
var = [(i) for i in friends]

Should do what you want, right?

edited Apr 19, 2022 at 11:16

answered Apr 19, 2022 at 11:06

Irgendniemand

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Comments

tripleee · Accepted Answer · 2016-06-20 08:35:37Z

0

If you want to join the values in friends into a comma-separated string, that would be

s = ','.join(friends)

If you want to include quotes around the names, maybe something like

s = ','.join(['"{0}"'.format(x) for x in friends])

answered Jun 20, 2016 at 8:35

tripleee

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Comments

CheezBiscuit · Accepted Answer · 2016-06-20 08:40:34Z

0

Try this at the end of the loop:

the_variable = the_variable + i

However, if you are to do this, you should add a space to the end of every item in the dictionary, otherwise it will output:

JoeZoeBradAngelinaZukiThandiParis

answered Jun 20, 2016 at 8:40

CheezBiscuit

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Comments

Dayantat · Accepted Answer · 2018-09-10 05:56:17Z

0

I would use a dictionary instead, as I too spent a while looking into this, and determined that a dictionary would be easy enough.

    friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
    dict= {}
    for i in friends:
       dict[i] = i

    print(dict)
    print(dict['Zuki'])
    dict['Zuki'] = "Tim Smith"

    print(dict['Zuki'])

The Other option would be to just call the number:

    print(friends[0])

As for automatic assignment I haven't found a way to do it.

answered Sep 10, 2018 at 5:56

Dayantat

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