I converted an NSIndexSet to an [Int] array using the answer at https://stackoverflow.com/a/28964059/6481734 I need to do essentially the opposite, turning the same kind of array back into an NSIndexSet.
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5 Answers
Swift 3
IndexSet can be created directly from an array literal using init(arrayLiteral:), like so:
let indices: IndexSet = [1, 2, 3]
Original answer (Swift 2.2)
Similar to pbasdf's answer, but uses forEach(_:)
let array = [1,2,3,4,5,7,8,10]
let indexSet = NSMutableIndexSet()
array.forEach(indexSet.add) //Swift 3
//Swift 2.2: array.forEach{indexSet.addIndex($0)}
print(indexSet)
This will be a lot easier in Swift 3:
let array = [1,2,3,4,5,7,8,10]
let indexSet = IndexSet(array)
Wow!
Swift 3+
let fromRange = IndexSet(0...10)
let fromArray = IndexSet([1, 2, 3, 5, 8])
Added this answer because the fromRange option wasn't mentioned yet.
Comments
Swift 4.2
From existing array:
let arr = [1, 3, 8]
let indexSet = IndexSet(arr)
From array literal:
let indexSet: IndexSet = [1, 3, 8]
Comments
You can use a NSMutableIndexSet and its addIndex method:
let array : [Int] = [1,2,3,4,5,7,8,10]
print(array)
let indexSet = NSMutableIndexSet()
for index in array {
indexSet.addIndex(index)
}
print(indexSet)
