how to count a array of specific words in a string php

Question

I need to count some specific words in string(How many times some word occurs in a string), How can I do it in php?

Example;

$words = array("woman", "murder", "rape", "female", "dowry");

$string = "A dowry deaths is a murder or suicide of a married woman caused by a dispute over her dowry.[4] In some cases, husbands and in-laws will attempt to extort a greater dowry through continuous harassment and torture which sometimes results in the wife committing suicide";

The first item is the bundle of some word, If this word match with below string increase its value....

Example of result like be:

dowry= 1;
murder =2;
women =5;

I just tried with substr_count , but this count only one words at a time, I needs several words to count at a time... php.net/manual/en/function.substr-count.php — MD. ABU TALHA
– MD. ABU TALHA, Commented Jun 23, 2016 at 13:10

Jayesh Chitroda · Accepted Answer · 2016-06-23 13:10:03Z

3

Try:

substr_count — Count the number of substring occurrences

$string = "A dowry deaths is a murder or suicide of a married woman caused by a dispute over her dowry.[4] In some cases, husbands and in-laws will attempt to extort a greater dowry through continuous harassment and torture which sometimes results in the wife committing suicide";

$words = array("women", "murder","rape","female","dowry");

foreach($words as $word) {
   echo $word." occurance are ".substr_count($string, $word)." times <br />";
}

Output:

women occurance are 0 times

murder occurance are 1 times

rape occurance are 0 times

female occurance are 0 times

dowry occurance are 3 times

answered Jun 23, 2016 at 13:10

Jayesh Chitroda

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1 Comment

echo Over a year ago

If the given string has a word say 'deathswomen' then it will return women occurance are 1 times which I think is not correct if you want to count only complete words and not just substring.

splash58 · Accepted Answer · 2016-06-23 13:09:25Z

2

function substr_count does what you want

foreach($words as $word)
  echo $word .' ' . substr_count($string, $word) . "\n";

result

women 0
murder 1
rape 0
female 0
dowry 3

demo

answered Jun 23, 2016 at 13:09

splash58

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Comments

user4962466 · Accepted Answer · 2016-06-23 13:25:46Z

1

using substr_count is going to be straightforward

$string = 'I just ate a delicious apple, and John ate instead a banana ice cream';
$words = ['banana', 'apple', 'kiwi'];
foreach($words as $word) {
    $hashmap[$word] = substr_count($string, $word);
}

now $hashmap contains an associative array with word => occurrences

array(3) {
  ["banana"] => int(1)
  ["apple"]  => int(1)
  ["kiwi"]   => int(0)
}

answered Jun 23, 2016 at 13:25

user4962466

Comments

Mennolp · Accepted Answer · 2016-06-23 13:16:49Z

0

You can Split the string into words and then loop through the array of words and check if it is one of the words inside the $words array is the same.

$arrayOfString = explode(" ", $string); //splitting in between spaces will return a new array
for ($i = 1; $i <= $arrayOfString.count(); $i++) //loop through the arrayOfString array
{
    for($j = $words.count(); $j >= 1; $j--)//loop through the words array
    {
         if($arrayOfString[i] == $words[j])
         {
              echo("You have a match with: " + $words[j]); //Add your count logic here
         }
    }
}

Hopefully this works for you.

There are probably better ways for you to do this, but I like this logic myself.

answered Jun 23, 2016 at 13:16

Mennolp

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1 Comment

user4962466 Over a year ago

this is not java dude

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