Initialize multiple values in a struct using one function

Question

I would like to initialize multiple variables in a struct using the same function like so:

type temp struct {
    i int
    k int
}

func newtemp(age int) *temp{
    return &temp{
        i, k := initializer(age)
    }
}
func initializer(age int)(int, int){
    return age * 2, age * 3   
}

however, I can not due to having to use : to initialize variables when creating a struct, is there any way I can do something that is valid yet like the code above?

you can have the initizalizer func take references: func initializer(i1 *int, i2 *int) { *i1=1; *i2=2} and pass t:= &temp{}; initializer(&t.i, &t.k) into it — Adam Vincze
– Adam Vincze, Commented Jun 24, 2016 at 6:33
but it looks like a hack to me, can you maybe give more detail on why you would want to have this initializer function separate from the newTemp ? — Adam Vincze
– Adam Vincze, Commented Jun 24, 2016 at 6:34
"I would like to <do something the language spec does not allow>." does not make a very good question. — Volker
– Volker, Commented Jun 24, 2016 at 6:43

icza · Accepted Answer · 2016-10-16 18:23:30Z

8

Using composite literal you can't.

Using tuple assignment you can:

func newtemp(age int) *temp{
    t := temp{}
    t.i, t.k = initializer(age)
    return &t
}

Testing it:

p := newtemp(2)
fmt.Println(p)

Output (try it on the Go Playground):

&{4 6}

edited Oct 16, 2016 at 18:23

answered Jun 24, 2016 at 6:56

icza

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