I am getting error while executing Linux bash script

Question

I am getting the following error while executing the script in file "handoff":

sh handoff
'andoff: line 5: syntax error near unexpected token `do
'andoff: line 5: `  do

Here is the content of the file:

cat handoff
while [ 1 ]; do
   credencemove
  k=0
  for n in `cat credencemove.txt`
  do
    status[$k]=$n
    k=`expr $k + 1`
  done
  for m in `cat logsequence.lst`
  do
    status[$k]=$m
    k=`expr $k + 1`
  done
   ls -lrt | grep arch_credence_1 | tail -1 | cut -c 68- | tr -d 'ah_.log.gz' | cut -c -5 > credencereceived.txt
  for o in `cat credencereceived.txt`
  do
    status[$k]=$o
    k=`expr $k + 1`
  done
   clear
   tput bold
   echo "         Received Applied Moved"
   echo "         ========================"
   echo " "
   echo " Credence1 -> ${status[6]} \c"
   echo "  ${status[3]} \c"
   echo "  ${status[0]}"
   tput rmso
   echo " "
   echo "Waiting 15 Minuites for applying further logs..."
   echo "Press ctrl + c to exit"
   sleep 900
done

Why did you put the question in an answer? You should edit your question and add it there. — l'L'l
– l'L'l, Commented Jun 24, 2016 at 11:37
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. — abarisone
– abarisone, Commented Jun 24, 2016 at 12:37

mob · Accepted Answer · 2016-06-24 16:42:41Z

1

You have carriage return characters (\r) in your bash script, as if the script were created on a Windows text editor.

Cleanse your script with dos2unix.

answered Jun 24, 2016 at 16:42

mob

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