Python operator module equivalent in Java for basic method references

Question

As of Java 8, method references exist. I have a simple interface which I would like to use existing (preferably in a java.something package) method references to implement.

public class Calculator {
    private interface BinaryFunction<A, B, R> {
        R apply(A a, B b);
    }

    private <A, B, R> R apply(BinaryFunction<A, B, R> binaryFunction, A a, B b) {
        return binaryFunction.apply(a, b);
    }

    public static void main(String [] args) {
        Calculator calculator = new Calculator();
        calculator.apply((a, b) -> a + b, 1, 2);            // 3
        calculator.apply(Math::addExact, 1, 2);             // 3
        calculator.apply((a, b) -> a || b, true, false);    // true
//        calculator.apply(?::?, true, false);              // true
    }
}

Math::addExact isn't the same as +, but it's close enough for me--I actually prefer getting ArithmeticException("integer overflow") thrown for my purposes.

If this were Python, I'd use the operator module, but I don't know if there is such a thing in Java.

So is there any static method in a java.something package that can go in the ?::? part which is equivalent to the || operator?

Are you asking for a method that does || on a pair of inputs? — dimo414
– dimo414, Commented Jun 28, 2016 at 5:54

Timothy McCarthy · Accepted Answer · 2016-06-28 05:53:37Z

3

I use the java.lang.Boolean.logicalOr(boolean, boolean) method for this purpose.

So in your case you would use:

calculator.apply(Boolean::logicalOr, true, false);

answered Jun 28, 2016 at 5:53

Timothy McCarthy

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