PHP preg_replace replace between slash

Question

I have a PHP function which is supposed to remove a value with its starting / and ending / from a given URL.

for example: remove /page_###/ from http://my-domain.com/search/page_2/order_asc. the result will be: http://my-domain.com/search/order_asc.

but also the URL may be like this: http://my-domain.com/search/order_asc/page_2. there is no ending / in the end;

function stripDir($url, $mask){
    return preg_replace('/' . $mask . '[\s\S]+?/', '', $url);
}

the above function should be able to remove page_5 from following URLS... stripDir('http://my-domain.com/search/page_5/order_asc', 'page') and stripDir('http://my-domain.com/search/order_asc/page_5', 'page')

chris85 · Accepted Answer · 2016-06-29 18:18:35Z

3

The /s in your current regular expression are delimiters, not the starting and ending characters you are looking for. Try changing the delimiter and it should work. Also if the trailing / is optional you should modify the regex I think:

~/page_[\s\S]+?(/|\z)~

or per your function:

~/' . $mask . '[\s\S]+?(/|\z)~

would work for you.

Demo: https://regex101.com/r/sH7bE2/3
Demo of just modified delimiters: https://regex101.com/r/sH7bE2/2
Demo of original regex: https://regex101.com/r/sH7bE2/1

Also since you are checking for the starting and ending / you're going to want to re-place one of those /s.

With substitution demo: https://regex101.com/r/sH7bE2/4

edited Jun 29, 2016 at 18:18

answered Jun 29, 2016 at 18:11

chris85

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spirit · Accepted Answer · 2016-06-29 18:13:32Z

2

function stripDir($url, $mask) {
    return preg_replace('/\/' . preg_quote($mask, '/') . '[^\/]+/', '', $url);
}

edited Jun 29, 2016 at 18:13

answered Jun 29, 2016 at 18:09

spirit

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1 Comment

chris85 Over a year ago

Answers should have a write up with them.

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