I need to be able to have a callback on execution of a function after ready
jQuery(document).ready(function() {
execute function 1, only when finish
do function 2
});
what is the good way to do that ?
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and what is the problem?Alexander_F– Alexander_F2010-09-28 13:31:34 +00:00Commented Sep 28, 2010 at 13:31
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What is the "something" you're trying, is it asynchronous?Nick Craver– Nick Craver2010-09-28 13:32:19 +00:00Commented Sep 28, 2010 at 13:32
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i have no sure way to know the function 1 is finish before doing finction 2menardmam– menardmam2010-09-28 13:33:16 +00:00Commented Sep 28, 2010 at 13:33
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Are you talking about .queue() ?Incognito– Incognito2010-09-28 13:35:46 +00:00Commented Sep 28, 2010 at 13:35
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What is function 1? In almost all cases, you know it's done just because the control came back to you and went to function 2. You mean it's asyncronous then?Tesserex– Tesserex2010-09-28 13:36:28 +00:00Commented Sep 28, 2010 at 13:36
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4 Answers
The following execute once the document has been loaded:
$(function(){
DoSomething();
});
function DoSomething()
{
SomethingElse(); // depends what you're doing in DoSomething()
}
function SomethingElse()
{
}
Comments
JavaScript is single-threaded. Nothing happens simultaneously. However, if fn1 is an async call, the thread will execute fn2 often before fn1's return value is ready. That's what makes JavaScript "racy."
If you have multiple aysnc calls in a series, then you either have to manage a series of NESTED callbacks or make a queue using the Active Object pattern. jQuery has one (mentioned). I wrote a library that does this called proto-q: http://code.google.com/p/proto-q/
Comments
yes this is a good way. you can use: (function(){}); if you are not using javascripts libs other than jQuery for ready
Comments
you can let function1 call a second function then the third one, and so on. but it is allways line by line
