I have a pattern that looks something like this .
var a ;
var b;
var obj = {
aa : 'This is what I want'
};
I want the text between aa : ' and '};
There might be multiple occurrences of this, but I would like to have the first one.
I have tried awk , grep and sed. But none of them gave me the perfect result, but spit out entire code.
What I have tried till now :
grep -Po "aa : \K.*(?= \'};)"
sed -e 's/aa :\(.*\)\n};/\1/'
Please try the following:
awk 'BEGIN {Found = 0;} /^aa :/{Found = 1; } /^};/{Found = 0;} {if(Found) {print $0;}}'
aa : 'This is what I want'};Using grep -oP you can use match reset \K:
grep -oP "\baa\s*:\s*'\K[^']+" file
This is what I want
If I really bend it in AWK:
BEGIN {
RS="- -it is not the spoon that bends, it is only yourself"
FS="(aa : '|'};)"
}
{
print $2
}
With GNU awk for multi-char RS:
$ awk -v RS="aa[[:space:]]*:[[:space:]]*'[^']*'[[:space:]]*}[[:space:]]*;" -F"'" '{$0=RT; print $2; exit}' file
This is what I want
Here is a another solution, using sed:
echo $'var obj = {\naa: \'This is what I want\'\n};
var obj2 = {\naa: \'Unwanted\'\n};' | \
sed -ne $'/aa:/ {N;s/aa: \'\\(.*\\)\'\\n.*/\\1/;T;p;q}'
T;p;q prints the replacement on the first match and quits, and continues with next line otherwise.
