Javascript replace multiple chars at once

Question

Here is my array and string:

var array = new Array('üÜ', 'ıI', 'iİ', 'ğĞ', 'şŞ', 'çÇ');
var string = 'İSTANBUL, ÜSKÜDAR, Çarşamba'

I'd to replace every (for ü) to [üÜ]. I mean [üÜ]SK[üÜ]DAR. Can anyone help me?

Zohaib Ijaz · Accepted Answer · 2016-07-02 22:26:42Z

3

You can use replace() method

string.replace(/ü|Ü/g, '[üÜ]')

For all matches,

array.forEach(function(key){
    string = string.replace(new RegExp('['+ key +']', 'g'), '['+ key +']');
});

edited Jul 2, 2016 at 22:26

answered Jul 2, 2016 at 21:56

Zohaib Ijaz

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2 Comments

cafoob Over a year ago

how can i replace all chars in array with this method?

Zohaib Ijaz Over a year ago

I though you can figure out from this part. Ok let me update my answer.

toto · Accepted Answer · 2016-07-02 22:45:10Z

0

function replaceAll(source, search, replace, ignoreCase) {
    //SCAPE SPECIAL CHARACTERES.
    var search1 = search.toString().replace(/([.*+?^=!:${}()|\[\]\/\\])/g, "\\$1");
    //IGNORE CASE SENSIVITY.
    var ignore = (ignoreCase) ? "gi" : "g";
    var result = source.replace(new RegExp(search1, ignore), replace);
    return result;
}


var array = new Array('üÜ', 'ıI', 'iİ', 'ğĞ', 'şŞ', 'çÇ');

for (var i=0; i < array.length; i++){
    array[i] = replaceAll(array[i],"ü", "üÜ",true);
}

answered Jul 2, 2016 at 22:45

toto

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