How to extract all substrings with regex pattern matching in elixir

Question

String: Lorem ipsum {{dolor}} sit {{amet}}, consectetur adipisicing {{elit}},

I want to extract a list of all tags which are wrapped in {{ }} from above mentioned string and work on them i.e check db if they exist or not and than replace them as markdown link as follows.

[substring](/tag/:substring_id)

i can replace them with

String.replace(string, ~r/\{\{.+?\}\}/, "new substring")

but this doesn't help me because i can't work on substrings i.e check the db.

i didn't find any String.scan or String.find type of functions which returns substrings as a list. if you know how to do it than please let me know.

Thanks in advance for your effort and time :)

Is the string constant except for the portion in the {{}} part? I ask because if it is constant otherwise you could use pattern matching for this too. — Onorio Catenacci
– Onorio Catenacci, Commented Jul 11, 2016 at 0:41

davidwebster48 · Accepted Answer · 2024-05-20 13:05:28Z

5

You can use the Regex.scan/3 function if you simply want to extract the matched regex expression into a list of values.

Regex.scan(~r/\{\{.+?\}\}/, string)
#[["{{dolor}}"], ["{{amet}}"], ["{{elit}}"]]

edited May 20, 2024 at 13:05

davidwebster48

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answered Jul 10, 2016 at 2:39

coderVishal

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Comments

Dogbert · Accepted Answer · 2016-07-10 02:35:15Z

4

You can use Regex.replace/4 with a function as replacement:

db = %{"dolor" => 1, "elit" => 2}

string = "Lorem ipsum {{dolor}} sit {{amet}}, consectetur adipisicing {{elit}},"

Regex.replace(~r/{{(.+?)}}/, string, fn whole, tag ->
  if id = db[tag] do
    "[#{tag}](/tag/#{id})"
  else
    whole
  end
end) |> IO.puts

Output:

Lorem ipsum [dolor](/tag/1) sit {{amet}}, consectetur adipisicing [elit](/tag/2),

answered Jul 10, 2016 at 2:35

Dogbert

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