Find variable in files using RegEx

Question

I want read out variable which is mentioned below in file.

#define xyz_u8 abc_0x0_u8 = 0x0 (for hex)
#define xyz_f16 abc_MOD1_f32 = -0.1f (for int and float)
#define xyz abc_YY = YY_ZZ (for others)

I am using

re.compile(r"^#define\s+(\w+)\s+(\w+)(0[xX][0-9a-fA-F]+)")

for reading hex, but i am not able to get value from '='. Can anyone correct the regular expression.

What about a mere .* or .+ at the end? Try (?i)^#define\s+(\w+)\s+(\w+) = (.+) — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 11, 2016 at 7:22
Wiktor, How can i find regex for 'SET_abc_1(GET_xyz_2())' i am trying as re.compile(r"^(SET\w+)(GET\w+)") but it is not searching. Also i want to find variable like this "SET_abc(GET_xyz()/2 + GEt_qwe_3()/2)" — user2030113
– user2030113, Commented Jul 13, 2016 at 11:03
Isn't it a new question already? No idea what you need, really. Try (SET\w+)\((GET\w+)(?:(?:\([^()]*\)/\d+)?\W+(GET\w+))?. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 13, 2016 at 11:19

Wiktor Stribiżew · Accepted Answer · 2016-07-11 07:28:55Z

1

I suggest

^#define\s+(\w+)\s+(\w+) = (.+)

Use it with the re.I and re.M (if you have multiline input).

Pattern explanation:

^ - start of string (or line if re.M is used)
#define - a sequence of literal characters
\s+ - 1 or more whitespaces
(\w+) - Group 1 capturing one or more word ([a-zA-Z0-9_]) chars
\s+ - 1 or more whitespaces
(\w+) - Group 2 capturing one or more word ([a-zA-Z0-9_]) chars
= - space, =, space (you may add + after each space to allow 1 or more spaces, or * to allow 0 or more spaces)
(.+) - Group 3 that will capture the rest of the line.

answered Jul 11, 2016 at 7:28

Wiktor Stribiżew

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