Running multiple processes through shell script

Question

I have a server executable myserver. I have to start 5 instances of it with different IP addresses (provided through commandline). This is what I have tried:

for i in `seq 1 5`
do
    ip="127.0.0.$i"
    myserver $ip
done

The problem is that after starting first myserver, the control does not come to the terminal. How can I start the processes in background?

Appending with & i.e. myserver $ip & did not help. Most likely, I am doing something wrong with the last & that is used to run processes in background.

Edit: myserver has to continuously listen to a socket bound to its IP and a default port. Therefore, it has an infinite loop inside it.

John Zwinck · Accepted Answer · 2016-07-13 03:29:06Z

3

for i in {1..5}
do
    ip="127.0.0.$i"
    myserver "$ip" &
done

wait # for all backgrounded jobs to finish

answered Jul 13, 2016 at 3:29

John Zwinck

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1 Comment

Мона_Сах Over a year ago

The wait at the end is classy. :) but may be optional

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