python regular expression error

Question

I am trying do a pattern search and if match then set a bitarray on the counter value.

runOutput = device[router].execute (cmd)
            runOutput = output.split('\n')
            print(runOutput)
            for this_line,counter in enumerate(runOutput):
                print(counter)
                if  re.search(r'dev_router', this_line) :
                    #want to use the counter to set something

Getting the following error:

if re.search(r'dev_router', this_line) :

2016-07-15T16:27:13: %ERROR: File "/auto/pysw/cel55/python/3.4.1/lib/python3.4/re.py", line 166,

in search 2016-07-15T16:27:13: %-ERROR: return _compile(pattern, flags).search(string)

2016-07-15T16:27:13: %-ERROR: TypeError: expected string or buffer

alecxe · Accepted Answer · 2016-07-15 23:51:13Z

2

You mixed up the arguments for enumerate() - first goes the index, then the item itself. Replace:

for this_line,counter in enumerate(runOutput):

with:

for counter, this_line in enumerate(runOutput):

You are getting a TypeError in this case because this_line is an integer and re.search() expects a string as a second argument. To demonstrate:

>>> import re
>>>
>>> this_line = 0
>>> re.search(r'dev_router', this_line)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/Users/user/.virtualenvs/so/lib/python2.7/re.py", line 146, in search
    return _compile(pattern, flags).search(string)
TypeError: expected string or buffer

By the way, modern IDEs like PyCharm can detect this kind of problems statically:

(Python 3.5 is used for this screenshot)

edited Jul 15, 2016 at 23:51

answered Jul 15, 2016 at 23:44

alecxe

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1 Comment

cwahls Over a year ago

And then the counter can be something simple as: before loop counter = 0, and if matched counter += 1

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