Remove values with numbers from array in php

Question

I have an array of categories getting values from database

<?php foreach ($category_1['children'] as $category_2) { ?>
  <li><a href="<?php echo $category_2['href']; ?>">
<?php echo $category_2['name']; ?></a>
<?php } ?>

It returns values like

8.5" x 14" (Tri-Fold) 8.5" x 2.75" 8.5" x 3.667" (1/3 Page) 8.5" x 5.5" 8.5" x 5.5" (1/2 Page) 80lb gloss book, 16 Page Wall Calendar 9" x 12" Envelope 9" x 14.5" Booklets/Catalogs Bookmarks Brochures Business Cards Calendars

The problem is that I want to remove the values which have numbers in it and display the values with names only. For eg.

Booklets/Catalogs Bookmarks Brochures Business Cards Calendars

So how can I remove the values with numbers from the array. Can it be done with the array_filter using wildcard.

RomanPerekhrest · Accepted Answer · 2016-07-20 07:52:32Z

3

The solution using array_filter and preg_match functions:

...

$category_1['children'] = array_filter($category_1['children'], function($v){
    return !preg_match("/\d/", $v["name"]);
});
// now the $category_1['children'] array contains only items with needed "names"

answered Jul 20, 2016 at 7:52

RomanPerekhrest

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Comments

Ivan · Accepted Answer · 2016-07-20 08:13:09Z

I have tested the following code and it works. It loops through the array with a for loop and when it finds a row with an href that's not empty it removes the element from array. You can see bellow that I have created the array $category_1['children'] :

<?php


$category_1['children'] = array(
  array('href' => 'j', 'name' => 'aa'),
  array('href' => '', 'name' => 'bb'),
  array('href' => 'j', 'name' => 'aa'),
  array('href' => 'l', 'name' => 'aaas'),
  array('href' => '', 'name' => 'aa'),
  array('href' => '', 'name' => 'cc')
);

Now time to sort it out :

$array = $category_1['children'];
for ($i=0; $i < count($category_1['children']); $i++) {
  if($category_1['children'][$i]['href'] != null) {
    unset($category_1['children'][$i]);
  }
}

Verify result :

print_r($category_1['children']);

Anshum Chauhan · Accepted Answer · 2016-07-20 07:57:21Z

0

<?php foreach ($category_1['children'] as $category_2) { 
        $str = $category_2['name'];
         preg_match('!\d+!', $str, $matches);
        if(empty($matches))){
        ?>
        <li><a href="<?php echo $category_2['href']; ?>"><?php echo $category_2['name']; ?></a>
    <?php } 
        }?>

preg match checks for numeric value in category name and if there is no numeric data, displays the list.

answered Jul 20, 2016 at 7:57

Anshum Chauhan

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Comments

Amit Rajput · Accepted Answer · 2016-07-20 07:58:01Z

0

Here is the simple way:

<?php foreach ($category_1['children'] as $category_2) { ?>

<?php if(1 !== preg_match('~[0-9]~', $category_2['name'])){ ?>

  <li><a href="<?php echo $category_2['href']; ?>">

      <?php echo $category_2['name']; ?></a></li>

<?php } } ?>

answered Jul 20, 2016 at 7:58

Amit Rajput

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Comments

pradeep1991singh · Accepted Answer · 2016-07-20 08:07:14Z

0

You can simply use regex '/^[a-zA-Z ]*$/' and put a check on it: e.g.

<?php foreach ($category_1['children'] as $category_2) {

  if(preg_match('/^[a-zA-Z ]*$/', category_2['name'])) {?>

   <li><a href="<?php echo $category_2['href']; ?>"><?php echo $category_2['name']; ?></a></li>

  <?php }

} ?>

answered Jul 20, 2016 at 8:07

pradeep1991singh

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Comments

phaberest · Accepted Answer · 2016-07-20 08:24:23Z

0

You are right, array_filter() is the solution.

$new_array = array_filder($category_1['children'], function ($element) {
    return !preg_match("~[0-9]~", $element['name'])
}

I didn't test it, but it should work.

Do this before the foreach() and check values with a die(var_dump($new_array));

// Edit The solution provided by @romanperekhrest is a better preg_match, anyway if you don't want to use regular expressions, an alternative would be

!strpbrk($element, '1234567890')

It's obviously intended inside the closure.

edited Jul 20, 2016 at 8:24

answered Jul 20, 2016 at 7:55

phaberest

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