--debug command line argument in Python

Question

When I introduce to the command line "--debug" argument I need to set variable "debug", from my python script, to the value 1.

I've tried something, but I have to write "--debug=1" to the command line to set variable.

parser = argparse.ArgumentParser()
parser.add_argument("--debug", default=2)

When I run the command:

python script.py --rev1=1.2 --rev2=1.5 --debug

my variable "debug" should have value 1.

vaultah · Accepted Answer · 2016-07-21 08:42:13Z

2

If you're interested to know whether a certain command line flag has been passed to your script, you'd set the action argument of Argument.add_argument to store_true.

parser.add_argument('--debug', action='store_true')

Then parser.parse_args().debug will have the value of True if --debug was present and False otherwise.

$ python script.py
parser.parse_args() returned Namespace(debug=False)
$ python script.py --debug
parser.parse_args() returned Namespace(debug=True)

answered Jul 21, 2016 at 8:42

vaultah

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1 Comment

hpaulj Over a year ago

action='store_const' along with default=2 and const=1 could be used to set values of 1 or 2. store_true is a subclass of store_cont.

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