Sending multiple parameters in url as GET request in django?

Question

I am sending a GET request from jquery as:

http://127.0.0.1:8000/viewspecs/itemdetails?param1="+variable1+"&param2="+ variable2

The urls.py file in django for this section looks something like:

url(r'^viewspecs/itemdetails?param1=(?P<specs_search_item>[\w\+%_ ./-]+)&param2=(?P<item_price>[0-9])$', views.specsView),

When I access the address ,I get a page not(404) error. why ?

why not define url like this viewspecs/itemdetails and access using viewspecs/itemdetails?param=search_item — Raja Simon
– Raja Simon, Commented Jul 25, 2016 at 8:05
In the same way how would you accomplish this for two parameters? — Arpan Kc
– Arpan Kc, Commented Jul 25, 2016 at 8:10

Nishant Nawarkhede · Accepted Answer · 2016-07-25 08:18:58Z

13

Your url should be,

url(r'^viewspecs/itemdetails/$', views.specsView),

And view will be like,

def specsView(request):
    param1 = request.GET['param1']
    param2 = request.GET['param2']

And if you want to pass parameters as,

http://127.0.0.1:8000/viewspecs/itemdetails/param1/param2

then urls will be,

url(r'^viewspecs/itemdetails/(?P<param1>[\w-]+)/(?P<param2>[\w-]+)/$', views.specsView),

view will be like this,

def specsView(request, param1, param2):
    pass

answered Jul 25, 2016 at 8:11

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1 Comment

Thanks man! This solved my problem. Learned something new today. By the way I found the first method easier .

Satyam Shree · Accepted Answer · 2021-06-27 15:09:51Z

0

If You are going to use this method

def specsView(request):
    param1 = request.GET['param1']
    param2 = request.GET['param2']

use .get() function

def specsView(request):
    param1 = request.GET.get('param1')
    param2 = request.GET.get('param2')

as this will not throw any errors even if the parameters are missing (or optional)

answered Jun 27, 2021 at 15:09

Satyam Shree

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