javascript Function string.slice

Question

I'm trying to do this following javascript exercise here: Create a function called mixUp. It should take in two strings, and return the concatenation of the two strings (separated by a space) slicing out and swapping the first 2 characters of each. You can assume that the strings are at least 2 characters long.

and here's my code:

var mixUP = function(a, b) {
  var sliceA = a.slice(0,2);
  var sliceAa = a.slice(2);
  var sliceB = b.slice(0,2);
  var sliceBb = b.slice(2);
  var string = sliceA + sliceBb + " " + sliceB + sliceAa;
  console.log(string);
};
mixUp(apple, pear);

Could anyone please help me out here coz it's not working for me. Thanks heaps!

Are apple and pear strings? I don't see quotes and I don't see their definition. — Mike Cheel
– Mike Cheel, Commented Jul 27, 2016 at 12:42

UTahir94 · Accepted Answer · 2016-07-27 12:47:57Z

1

The way I approached it was:

    function mixUp(stringA, stringB) {
        var sliceA = stringA.slice(0,2),
          sliceB = stringB.slice(0,2);
        return (sliceB + stringA.substring(2) + " " + sliceA +
          stringB.substring(2));
    }

Which gives you the desired output

answered Jul 27, 2016 at 12:47

UTahir94

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Comments

vaso123 · Accepted Answer · 2016-07-27 12:44:38Z

0

If you define mixUP call it, not mixUp last p is uppercase.

When you use strings, you need to add quotes around them:

var mixUp = function  (a, b) {
    var sliceA = a.slice(0, 2);
    var sliceAa = a.slice(2);
    var sliceB = b.slice(0, 2);
    var sliceBb = b.slice(2);
    var string = sliceA + sliceBb + " " + sliceB + sliceAa;
    console.log(string);
};
mixUp('apple', 'pear');

OUTPUT

apar peple

answered Jul 27, 2016 at 12:44

vaso123

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Comments

Cerbrus · Accepted Answer · 2016-07-27 12:45:13Z

0

Typo's:

mixUp(apple, pear);

should be:

mixUP('apple', 'pear');
    ^ ^     ^  ^    ^

You called mixUp instead of mixUP, and both apple and pear should be strings (Unless they are variables already)

That'll give you the desired result:

var mixUP = function(a, b) {
  var sliceA = a.slice(0,2);
  var sliceAa = a.slice(2);
  var sliceB = b.slice(0,2);
  var sliceBb = b.slice(2);
  var string = sliceA + sliceBb + " " + sliceB + sliceAa;
  console.log(string);
};

mixUP('apple', 'pear');

answered Jul 27, 2016 at 12:45

Cerbrus

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Comments

Sravan · Accepted Answer · 2016-07-27 12:46:45Z

0

Either change the function calling or the function definition to same name as you have taken different names for both.

  var mixUP = function(a, b) {
      var sliceA = a.slice(0,2);
      var sliceAa = a.slice(2);
      var sliceB = b.slice(0,2);
      var sliceBb = b.slice(2);
      var string = sliceA + sliceBb + " " + sliceB + sliceAa;
      console.log(string);
    };
    mixUP("apple", "pear"); // apar peple

edited Jul 27, 2016 at 12:46

answered Jul 27, 2016 at 12:44

Sravan

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1 Comment

vaso123 Over a year ago

apple is not defined.

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