How to output HTML from array in PHP

Question

Sorry if the subject is a bit strange. But I didn't know what else to name it.

I would like to style this peace of code to fit with the style of my website.

<?php 
  global $post;
  $opties = wp_get_post_terms($post->ID, 'Items', array("fields" => "names"));
  if (count($opties) > 0) {
      echo implode(', ', $opties);  
  }
?>

Right now it echo's

Item 1, Item 2, Item 3, etc...

I would like to have it echo the following:

<i class="fa fa-check" aria-hidden="true"></i>Item 1<br>
<i class="fa fa-check" aria-hidden="true"></i>Item 2<br>
<i class="fa fa-check" aria-hidden="true"></i>Item 3<br>

How to I get this code to do that? Thanks in advance!

Try combining foreach and echo.

Roman Hocke
– Roman Hocke

2016-07-28 10:04:37 +00:00
Commented Jul 28, 2016 at 10:04 — Roman Hocke
– Roman Hocke, Commented Jul 28, 2016 at 10:04

Daniel Waghorn · Accepted Answer · 2016-07-28 10:06:45Z

8

You can combine HTML easily by using the alternative syntax for foreach.

<?php 
    global $post;
    $opties = wp_get_post_terms($post->ID, 'Items', array("fields" => "names"));
    foreach ($opties as $o): ?>
        <i class="fa fa-check" aria-hidden="true"></i><?php echo $o ?></i>
    <?php endforeach; ?>

answered Jul 28, 2016 at 10:06

Daniel Waghorn

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Comments

Jayesh Chitroda · Accepted Answer · 2016-07-28 10:08:32Z

5

Use foreach loop to loop through all record and display it.

<?php 
  global $post;
  $opties = wp_get_post_terms($post->ID, 'Items', array("fields" => "names"));
  foreach($opties as $opt) {
     echo '<i class="fa fa-check" aria-hidden="true"></i>'.$opt.'<br>';
  }   
?>

edited Jul 28, 2016 at 10:08

answered Jul 28, 2016 at 10:05

Jayesh Chitroda

5,03915 silver badges18 bronze badges

1 Comment

Daredzik Over a year ago

count is not required, coz foreach do nothing on empty resource ;)

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