Two functions with different number of type parameters in Kotlin

Question

This two functions conflicts with each other. Is there a workaround for this issue?

inline fun <reified T: Any> foo() = ...
inline fun <reified T: Any, reified I: Any> foo() = ...

Thanks!

Edit:

I found convenient(at least for me) solution for this issue:

inline fun <reified T: Any> foo() = foo<T, MyDefaultType>()
inline fun <reified T: Any, reified I: Any> foo(type1: KClass<T> = T::class, type2: KClass<I> = I::class) = ...

It can be even concise if you choose to add only one parameter.

Later you can use it like this:

val x = foo<A, B>()
val y = foo<C>()

That's what I need.

yole · Accepted Answer · 2016-08-02 13:31:45Z

5

These functions have identical signatures from the compiler point of view. A type parameter is not part of a signature of a function; it can be inferred by the compiler automatically, and therefore does not serve to disambiguate calls to different overloads.

You need to assign different names to those functions.

answered Aug 2, 2016 at 13:31

yole

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Kirill Rakhman · Accepted Answer · 2016-08-02 09:32:36Z

0

Add the annotation @JvmName("foo2") to one of the functions.

answered Aug 2, 2016 at 9:32

Kirill Rakhman

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