Replace dictionary's empty values python

Question

First of all, I'm modifying another guy's code.

I'm trying to print the values of dictionary that correspond to a key like so:

print (map(str, dict[key]))

All works fine, but there are some fields that are printed with just the double quotes, like so ['some_value', '', 'other_value', etc...], what I'm trying to accomplish here, is to replace the single quotes '', with n/a

my approach, at first, was to do this: print (map(str.replace("\'\'", "n/a"), dict[key])), but I get the TypeError message: TypeError: replace() takes at least 2 arguments (1 given)

How can I work around this?

the values are read from a pickled file, which the other guy unpickled first. Ι know it's not much of a help, but this is all I've got... It's pretty poorly written code... — Jack
– Jack, Commented Aug 5, 2016 at 17:06

galaxyan · Accepted Answer · 2016-08-05 17:22:23Z

1

map function needs func and iterable

data = { '':'',1:'a'}
print (map( lambda x: x if x else 'n/a', data.values()))
['n/a', 'a']

for value as list:

data = { 'a' :[1,'',2]}
print (map( lambda x: str(x) if x else 'n/a', data['a']))
['1', 'n/a', '2']

edited Aug 5, 2016 at 17:22

answered Aug 5, 2016 at 17:14

galaxyan

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Comments

Camsbury · Accepted Answer · 2016-08-05 17:15:44Z

0

You should probably just expand to a for loop and write:

for value in dict.values():
    if value == "":
        print("n/a")
    else:
        print(str(value))

answered Aug 5, 2016 at 17:15

Camsbury

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1 Comment

Ted Klein Bergman Over a year ago

You could convert this to a list comprehension if you want to [print("n/a") if value == "" else print(str(value)) for value in dict.values()]

Asish M. · Accepted Answer · 2016-08-05 17:22:03Z

0

Try using

print([k if k else "n/a" for k in map(str, dict[key])])

edited Aug 5, 2016 at 17:22

answered Aug 5, 2016 at 17:10

Asish M.

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1 Comment

galaxyan Over a year ago

are you sure it work? are you saying [k for k in ['','1'] if k else "n/a"] will work?

Andrea · Accepted Answer · 2016-08-08 08:11:35Z

0

You could solve your problem in a more simple way without using map(). Just use list() than you can loop on every single character of your string (diz[key]) and then replace the empty space with the 'n/a' string as you wish.

diz[key] = 'a val'
[w.replace(' ', 'n/a') for w in list(diz[key])]
>> ['a', 'n/a', 'v', 'a', 'l']

edited Aug 8, 2016 at 8:11

answered Aug 5, 2016 at 17:18

Andrea

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