Update Database Using AJAX in Django

Question

So I have an AJAX command, which passes information to a views.py method (I have verified that the passing works from the HTML->urls.py->views.py, so that's all good), but once I have it in "views.py", I have no idea how to get it to update in the database itself.

I have tried to avoid using a forms.py file if possible, but if that is the only option I'll bend to it.

The AJAX function is as follows:

$.ajax({
    url : '/perform/acts/update/{{  act.id  }}/',
    type : "POST",
    data : {
        'csrfmiddlewaretoken' : "{{  csrf_token  }}",
        furtherData : furtherData
    },
    success : function(result) {}
});

The views.py function is...so far, lacking, to say the least, but this is where I'm sort of lost:

def update_act(request, furtherData_id):
    if request.method == 'POST':
      ?
      return HttpResponse(?)

A big reason for doing this this way was performing updates without reloading and without having to add another module. I have been using Django for only a couple weeks, so it could be something easy that I'm missing...

Any help much appreciated!

Volantines · Accepted Answer · 2016-08-09 16:27:55Z

4

def update_act(request,furtherData_id):
    from django.http import JsonResponse
    if request.method == 'POST': 
        obj=MyObj.objects.get(pk=furtherData_id)
        obj.data=request.POST['furtherData']
        obj.save()
        return JsonResponse({'result':'ok'})
    else:
        return JsonResponse({'result':'nok'}

answered Aug 9, 2016 at 16:27

Volantines

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1 Comment

souldeux Over a year ago

I feel like this is the "right answer" based on the parameters the OP provided, but this does blindly save the input to the DB. Using a ModelForm and supplying obj as an instance to that form would provide some data validation here.

GrvTyagi · Accepted Answer · 2016-10-19 16:49:20Z

2

Your view function:

def my_view_action(request, any_pk_id):
    from django.http import JsonResponse
    if request.method=='POST' and request.is_ajax():
        try:
            obj = MyModel.objects.get(pk=any_pk_id)
            obj.data_attr = request.POST['attr_name']
            obj.save()
            return JsonResponse({'status':'Success', 'msg': 'save successfully'})
         except MyModel.DoesNotExist:
            return JsonResponse({'status':'Fail', 'msg': 'Object does not exist'})
     else:
         return JsonResponse({'status':'Fail', 'msg':'Not a valid request'}

This function directly save data on your DB, For validate it first use form then proceed to save action.

---Steps---
- Create a form for model.
- Fill data on this model via request/object.
- Run validate on form then save to db via form or via model.

For more info https://docs.djangoproject.com/en/1.10/topics/forms/modelforms/#the-save-method

edited Oct 19, 2016 at 16:49

answered Aug 9, 2016 at 17:05

GrvTyagi

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1 Comment

A Campos Over a year ago

To access form data in the views just do request.POST

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